Question

How many milliliters of an aqueous solution of 0.193 M potassium carbonate is needed to

Answer 1

Answer:

295 mL

Explanation:

Given data:

Volume needed = ?

Molarity of solution = 0.193 M

Mass of salt = 7.90 g

Solution:

Molarity =  number of moles of solute / volume in L

Number of moles of salt = mass/molar mass

Number of moles of salt = 7.90 g/ 138.205 g/mol

Number of moles = 0.057 mol

Volume needed:

Molarity = number of moles / volume in L

0.193 M = 0.057 mol / volume in L

Volume in L = 0.057 mol /  0.193 M

Volume in L = 0.295 L

L into mL

0.295 L × 1000 mL/1L

295 mL