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3 years ago

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Mathematics

1 answer:

gavmur [86]3 years ago

4 0

Answer:

Step-by-step explanation:

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Leona has a large bag of apples. There are 180 apples in the bag. She uses 14of the apples to make some juice. She uses 20% of t

andreev551 [17]

Answer:

132.8 are left enjoy

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2 years ago

The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1

Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let $r$ represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

$\frac{dr}{dt}=7\ mm/hr$

Volume of cylinder is given by:

$V=\pi\ r^2h$

Finding derivative of the Volume with respect to time.

$\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}$

Plugging in the values given:

$\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)$

$\frac{dV}{dt}=252\pi$

Using $\pi=3.14$

$\frac{dV}{dt}=252(3.14)$

$\frac{dV}{dt}=791.28\ mm^3/hr$ (Answer)

Thus rate of change of the volume of the cylinder at that instant = $791.28\ mm^3/hr$

6 0

3 years ago

Is a triangle with sides of length 6ft, 21 ft, 23 ft. A right triangle?

gayaneshka [121]

Answer:

Step-by-step explanation:

By using the Pythagoras theorem, it can be easily determined that whether the triangle is right triangle or not.

Thus, $a^{2}+b^{2}=c^{2}$ where where a and b are the legs and c is the hypotenuse.

Let a=6ft, b=21ft and c=23ft, then

$a^{2}+b^{2}=c^{2}$

$(6)^{2}+(21)^{2}=(23)^{2}$

$36+441=(23)^{2}$

$477=529$

which is not possible, therefore the given triangle is not right triangle because it does not satisfy the Pythagoras theorem.

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3 years ago

Y>x-3, y<-x+3? I need a graph:(

olchik [2.2K]

Answer:

Then make one

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Combine the following fractions by addition or subtraction as directed.

Marina86 [1]

Answer: $\frac{6}{y^2-xy}-\frac{6}{x^2-xy}=\frac{6(x+y)}{xy(y-x)}$

Explanation:

Combining the fractions, we have:

$\begin{gathered} \frac{6(x^2-xy)-6(y^2-xy)}{(x^2-xy)(y^2-xy)} \\ \\ =\frac{6x^2-6xy-6y^2+6xy}{(x^2-xy)(y^2-xy)} \\ \\ =\frac{6x^2-6y^2}{x(x-y).y(y-x)} \\ \\ =\frac{6(x-y)(x+y)}{-xy(x-y)^2} \\ \\ =\frac{-6(x+y)}{xy(x-y)} \\ \\ =\frac{6(x+y)}{xy(y-x)} \end{gathered}$

8 0

1 year ago