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Oksana_A [137]
3 years ago
13

1. How would you explain that energy in animals' food was once energy

Chemistry
2 answers:
AleksAgata [21]3 years ago
8 0

Answer:

Explanation: That energy inanimals food, used for body repair,growth, motion .It maintain body warmth, once energy from the sun.

Tju [1.3M]3 years ago
4 0

Answer:

The energy released from food was once energy from the sun that was captured by plants in the chemical process that forms plant matter (from air and water). Food provides animals with the materials they need for body repair and growth and the energy they need to maintain body warmth and for motion.

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If an atom of chlorine had an atomic mass of 17 and it gained an electron what would you have?
Sonbull [250]
The atomic mass would not change since the mass of an electron is negligible compared to the mass of protons and neutrons
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3 years ago
If 2 objects have the same volume, but one has more mass than the other, are the densities the same or different? Explain
laiz [17]

The one with higher mass has a higher density because it fits more mass into the same amount of space (volume).

4 0
3 years ago
How many grams of Mg(NO3)2 would be produced? please show how you got the answer​
Len [333]

Answer:

148 grams of relative atomic mass

Explanation:

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nitrogen : 14

oxygen : 16

24 × 1

14 × 1 × 2

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What is the oxidation number of boron in Na(B(NO3)4)
Vitek1552 [10]

Answer:

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7 0
2 years ago
Read 2 more answers
V2 = (P1 × V1 × T2) (P2 × T1) A gas with a beginning pressure of 2 atm at a temperature of 300 K has a volume of 20 ml. What wil
rusak2 [61]

6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

V_1=20 ml

T_1=3

P_1=2 atm

T_2=200 K

P_2=4 atm

V_2=?

Using equation:

V_2 = \frac{P_1 X V_1 XT_2}{P_2 X T_1}

V_2 =\frac{2 atm  X 20 ml X200 K}{4 atm  X 300 K}

V_2 = 6.6 ml

Hence, 6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

Learn more about the ideal gas equation here:

#SPJ1

6 0
2 years ago
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