2 years ago

(ii) ן ( Solve 11-Jx+4 = 0 for real Question for 1 B)

Mathematics

1 answer:

tatyana61 [14]2 years ago

4 0

Answer:

x = 117

Step-by-step explanation:

Given

11 - $\sqrt{x+4}$ = 0 ( subtract 11 from both sides )

- $\sqrt{x+4}$ = - 11 ( square both sides )

(- $\sqrt{x+4}$ )² = (- 11)²

x + 4 = 121 ( subtract 4 from both sides )

x = 117

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