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Wewaii [24]
3 years ago
13

(ii) ן ( Solve 11-Jx+4 = 0 for real Question for 1 B)

Mathematics
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:

x = 117

Step-by-step explanation:

Given

11 - \sqrt{x+4} = 0 ( subtract 11 from both sides )

- \sqrt{x+4} = - 11 ( square both sides )

(- \sqrt{x+4} )² = (- 11)²

x + 4 = 121 ( subtract 4 from both sides )

x = 117

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What is the lateral area of the drawing?
aleksley [76]

40 mi² is your answer


They are 4 equal rectangle.

Area rectangle = w * l

5 * 2 = 10 mi² (area 1 rectangle)

then you multiply by 4

10 * 4 = 40 mi²

or

5 * 2 * 4 = 40 mi²

8 0
3 years ago
What is the vertex of the graph of y = –x^2
kozerog [31]

For y = -x², the vertex = (0,0)

8 0
4 years ago
Evaluate the expression. Drag the answer into the box to match the expression. 2⋅(3^6⋅3^−5)
dezoksy [38]

Answer:

6

Step-by-step explanation:

2( {3}^{6}  \times  {3}^{ - 5} ) \\  {3}^{6 - 5}  =  {3}^{1}  = 3 \\ 2 \times 3 = 6

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★ . ꜝꜞ ᳝ ࣪ hope that helped!  ʬʬ

8 0
3 years ago
BRAINLIEST!!
REY [17]

Answer:

Yes, the sum of any two sides is greater than the third.

Step-by-step explanation:

To determine whether the provided sides are the sides of a triangle check if the sum of two sides is more than the third side.

The length provided are: 8.5, 13 and 19.1.

  • Consider the sides 8.5 and 13:

        The sum is:

        8.5+13=21.5

        This sum is greater than the third side 19.1

  • Consider the sides 8.5 and 19.1:

        The sum is:

        8.5+19.1=27.6

        This sum is greater than the third side 13

  • Consider the sides 13 and 19.1:

        The sum is:

         13+19.1=32.1

        This sum is greater than the third side 8.5

Thus, the sides 8.5, 13 and 19.1 are sides of a triangle.

7 0
3 years ago
Read 2 more answers
Can someone please expand and simplify this
laila [671]

Pasos  

3(3−1)

Usa la propiedad distributiva para multiplicar 3 por 3−1.

(3)2−3

El cuadrado de 3 es 3.

3−3

B

Pasos  

5(10+2)

Usa la propiedad distributiva para multiplicar 5 por 10+2.

510+52

Factorice 10=5×2. Vuelva a escribir la raíz cuadrada del producto 5×2 como el producto de las raíces cuadradas 52.

552+52

Multiplica 5 y 5 para obtener 5.

52+52

Para multiplicar 5 y 2, multiplique los números bajo la raíz cuadrada.

52+10

4 0
3 years ago
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