Change occurs in the density of the gummy bear to change if we soaked it in isopropanol.
<h3>Effects on density by soaking isopropanol</h3>
We expect the density of the gummy bear to change if we soaked it in isopropanol because the gummy bear absorb the liquid which increase its density due to increasing weight of the gummy bear.
If a substance gains weight then its density also increases and we know that when the gummy bear was soaked in the isopropanol then its weight increases so its density is also changes so we can conclude that change occurs in the density of the gummy bear to change if we soaked it in isopropanol.
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Answer: the statements in 1 and 2 are true of IR spectroscopic region.
1. In general, the IR FUNDAMENTAL region has a longer wavelength region than the region we call the ultraviolet (uv) region.
2. We can sense some of the frequencies of the FUNDAMENTAL region of the IR as heat
Explanation:
IR has energy value between 10^-5eV - 10^-2eVwhile
UV has energy value of 4eV - 300eV
IR has low photon energy and cannot alter atoms and molecules while UV has sufficient energy to iodize atoms therefore UV has a higher energy band.
Infrared light falls just outside the visible spectrum, beyond the edge of what we can see as red.
Cloudy skies and precipitation. Rain is normally caused by water vapor within the condensation of the low pressure system.
In order to solve this, we need to know the standard cell potentials of the half reaction from the given overall reaction.
The half reactions with their standard cell potentials are:
<span>2ClO−3(aq) + 12H+(aq) + 10e- = Cl2(g) + 6H2O(l)
</span><span>E = +1.47
</span>
<span>Br(l) + 2e- = 2Br-
</span><span>E = +1.065
</span>
We solve for the standard emf by subtracting the standard emf of the oxidation from the reducation, so:
1.47 - 1.065 = 0.405 V
