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2 years ago

What is the ph of the solution prepared by dissolving 0.927 mol hcl in enough water to make a 150 l aqueous solution?

Chemistry

1 answer:

Brilliant_brown [7]2 years ago

8 0

Answer:

The answer to your question is pH = 2.2

Explanation:

Data

pH = ?

moles of HCl = 0.927

volume = 150 l

Process

1.- Calculate the Molar concentration of HCl

Molarity = moles / volume (L)

Molarity = 0.927 / 150

= 0.00618

2.- Calculate the pH

pH = -log [HCl]

Substitution

pH = -log [0.00618]

Result

pH = 2.2

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2 years ago

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Answer:

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Explanation:

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2 years ago

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Answer: The mass of carbon in given amount of carvone is 47.52 grams

Explanation:

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$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

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Putting values in equation 1, we get:

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Now, calculating the mass of carbon in carvone from equation 1, we get:

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3 years ago

Liters of a 2.40 M

kotykmax [81]

Answer:

1.42 L

Explanation:

Step 1:

The following data were obtained from the question :

Molarity of KBr = 2.40 M

Mole of KBr = 3.40 moles

Volume of solution =?

Step 2:

Determination of the volume of the solution.

Molarity of solution is simply the mole of the solute per unit volume the of solution. It is given as :

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 3.4/2.4

Volume = 1.42 L

Therefore, the volume of the solution is 1.42 L

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3 years ago

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2 years ago