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Dafna11 [192]
2 years ago
5

Which of the following statements describes the law of inertia?

Physics
1 answer:
Drupady [299]2 years ago
8 0

Answer:

B. objects remain in the same state of motion unless a force acts on them

Explanation:

Sana nakatulong

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A +7.5 nC point charge and a -2.0 nC point charge are 3.0 cm apart. What is the electric field strength at the midpoint between
eduard

Answer:

Ep= 3.8 10⁵ N/C

Explanation:

Conceptual analysis

The electric field at a point P due to a point charge is calculated as follows:

E = k*q/d²

E: Electric field in N/C

q: charge in Newtons (N)

k: electric constant in N*m²/C²

d: distance from charge q to point P in meters (m)

Equivalence

1nC= 10⁻⁹C

1cm= 10⁻²m

Data

k= 9*10⁹ N*m²/C²

q₁ =+7.5 nC = +7.5*10⁻⁹C  

q₂ =  -2.0 nC = -2.0*10⁻⁹C

d₁ =d₂ = 1.5cm = 1.5 *10⁻²m  = 0.015 m

Calculation of the electric fieldsat the midpoint (P) between the two charges

Look at the attached graphic:

E₁: Electric Field at point ;Due to charge q₁. As the charge q₁ is positive negative (q₁+), the field leaves the charge .

E₂: Electric Field at point : Due to charge q₂. As the charge q₂ is negative (q₂-) ,the field enters the charge

E₁ = k*q₁/d₁² = 9*10⁹ *7.5  *10⁻⁹/ ( 0.015 )² = 3*10⁵ N/C

E₂ = k*q₂/d₂²= 9*10⁹ *2*10⁻⁹/( 0.015 )² = 0.8*10⁵ N/C

The electric field at a point P due to several point charges is the vector sum of the electric field due to individual charges.

Ep= E₁ + E₂  

Ep= 3*10⁵ N/C +  0.8*10⁵ N/C

Ep= 3.8 10⁵ N/C

8 0
3 years ago
A student traveling at 8m/s on a bike has a mass of 182 KG and collides into a boulder and comes to a abrupt halt in 0.08 second
Delicious77 [7]
I hope this helps u !!

8 0
3 years ago
How do you know the force for an acceleration of zero?
Natali5045456 [20]
F=ma

So a=F/m

if acceleration is zero, resultant force is also zero.
5 0
3 years ago
ANSWER ASAP PLEASE!!
eimsori [14]
Sprry o cant see the words clearly
7 0
3 years ago
You wish to cook some pasta and so take some water and heat it on a stove. If you use 2000 grams of water with an initial temper
Ronch [10]

Answer:

the stove energy went into heating water is 837.2 kJ.

Explanation:

given,

mass of water = 2000 grams

initial temperature = 0° C

Final temperature = 100° C

specific heat of water (c) = 4.186 joule/gram

energy = m c Δ T                            

            = 2000 × 4.186 × (100° - 0°)

            = 837200 J                          

             = 837.2 kJ            

hence, the stove energy went into heating water is 837.2 kJ.

3 0
3 years ago
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