Answer:
The direction of the field is downward, and negatively charged particles will experience an upwards force due to the field.
F = N e E where E is the value of the field and N e the charge Q
M g = N e E and M g is the weight of the drop
N = M g / (e E)
N = 1.1E-4 * 9.8 / (1.6E-19 * 370) = 1.1 * 9.8 / (1.6 * 370) * E15 = 1.82E13
.00011 kg is a very large drop
Q = N e = M g / E = .00011 * 9.8 / 370 = 2.91E-6 Coulombs
Check: N = Q / e = 2.91E-6 / 1.6E-19 = 1.82E13 electrons
Answer:
W = - 5.01 10¹⁰ J
Explanation:
Work is defined by the expression
W = ∫ F.dr
Where the blacks indicate vectors, in the case the force is radial and the distance is also radial, whereby the scalar producer is reduced to an ordinary product
W = ∫ F dr
W = G m₁m₂ ∫ 1 /r² dr
W = G m₁ m₂2(-1 / r)
We evaluate between the lower limits r = Re and upper r = ∞
W = G m₁m₂ (-1 / Re + 1 / ∞)
W = - G m₁ m₂ / Re
Let's calculate
W = - 6.67 10⁻¹¹ 800 5.98 10²⁴ / 6.37 10⁶
W = - 5.01 10¹⁰ J
Answer:
λ = 6.602 x 10^(-7) m
Explanation:
In a double-slit interference experiment, the distance y of the maximum of order m from the center of the observed interference pattern on the screen is given as ;
y = mλD/d
Where;
D is the distance of the screen from the slits = 6.2 m
d is the distance between the two slits = 0.046 mm = 0.046 x 10^(-3) m
The fringes on the screen are 8.9 cm = 0.089 m apart from each other, this means that the first maximum (m=1) is located at y = 0.089 m from the center of the pattern.
Therefore, from the previous formula we can find the wavelength of the light:
y = mλD/d
So, λ = dy/mD
Thus,
λ = (0.046 x 10^(-3) x 0.089)/(1 x 6.2)
λ = 6.602 x 10^(-7) m
Answer:
<h3>The answer is 50 N</h3>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
<h3>force = mass × acceleration</h3>
From the question we have
force = 10 × 5
We have the final answer as
<h3>50 N</h3>
Hope this helps you
