3 years ago

Find the distance between (5, 9) & (-7, -7). Round to the nearest tenth.

Mathematics

2 answers:

prisoha [69]3 years ago

8 0

See picture hope it helps

a_sh-v [17]3 years ago

6 0

Answer:

Step-by-step explanation:

Distance = √[(-7-5)² + (-7-9)²]

= √[144 + 256]

= √400

= 20

You might be interested in

What is the measurements the for the angles

koban [17]

The angle TQS is 74° and the angle SQR is 106°

5 0

3 years ago

I really need help on rate changes!!

mrs_skeptik [129]

Answer: The third and fourth problem are linear

Step-by-step explanation:

3rd problem follows a pattern

X 6 5 4 3

Y 21 15 10 6

6x3+3=21

5x3=15

4x2+2=10

3x2=6

Problem 4 follows a pattern as well

X value goes up 1, Y value goes up 4

4 0

3 years ago

Negative 7 bigger or smaller than negative 8

dalvyx [7]

-7 is bigger than -8

4 0

3 years ago

Read 2 more answers

Leave answer in the simplest radical form.

slega [8]

$\cfrac{7x^{-\frac{3}{2}} ~~ y^{\frac{5}{2}} ~~ z^{-\frac{2}{3}}}{56 x^{-\frac{1}{2}} ~~ y^{\frac{1}{4}}}\implies \cfrac{7}{56}\cdot \cfrac{y^{\frac{5}{2}} ~~ y^{-\frac{1}{4}}}{x^{-\frac{1}{2}} ~~ x^{\frac{3}{2}} ~~ z^{\frac{2}{3}}}\implies \cfrac{1}{8}\cfrac{y^{\frac{5}{2}-\frac{1}{4}}}{x^{-\frac{1}{2}+\frac{3}{2}}~~ z^{\frac{2}{3}}}$

$\cfrac{y^{\frac{9}{4}}}{8x z^{\frac{2}{3}}}\implies \cfrac{\sqrt[4]{y^9}}{8x\sqrt[3]{z^2}}\implies \cfrac{\sqrt[4]{y (y^2)^4}}{8x\sqrt[3]{z^2}}\implies \cfrac{y^2 \sqrt[4]{y}}{8x\sqrt[3]{z^2}}$

7 0

2 years ago

Deb has of a brownie. She wants to divide it up into 's of a brownie so she can have it throughout the day. How many 's will she

qaws [65]

The answer would be 3

4 0

3 years ago