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Ulleksa [173]
3 years ago
13

Find the distance between (5, 9) & (-7, -7). Round to the nearest tenth.

Mathematics
2 answers:
prisoha [69]3 years ago
8 0
See picture hope it helps

a_sh-v [17]3 years ago
6 0

Answer:

Step-by-step explanation:

Distance = √[(-7-5)² + (-7-9)²]

= √[144 + 256]

= √400

= 20

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Read 2 more answers
Leave answer in the simplest radical form.
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\cfrac{7x^{-\frac{3}{2}} ~~ y^{\frac{5}{2}} ~~ z^{-\frac{2}{3}}}{56 x^{-\frac{1}{2}} ~~ y^{\frac{1}{4}}}\implies \cfrac{7}{56}\cdot \cfrac{y^{\frac{5}{2}} ~~ y^{-\frac{1}{4}}}{x^{-\frac{1}{2}} ~~ x^{\frac{3}{2}} ~~ z^{\frac{2}{3}}}\implies \cfrac{1}{8}\cfrac{y^{\frac{5}{2}-\frac{1}{4}}}{x^{-\frac{1}{2}+\frac{3}{2}}~~ z^{\frac{2}{3}}}

\cfrac{y^{\frac{9}{4}}}{8x z^{\frac{2}{3}}}\implies \cfrac{\sqrt[4]{y^9}}{8x\sqrt[3]{z^2}}\implies \cfrac{\sqrt[4]{y (y^2)^4}}{8x\sqrt[3]{z^2}}\implies \cfrac{y^2 \sqrt[4]{y}}{8x\sqrt[3]{z^2}}

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