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joja [24]
3 years ago
6

Is the following equation balanced? FeCl₃ + MgO → Fe₂O₃ + MgCl₂ A. Yes B. No

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
4 0

Answer:

The answer is B) No.

Explanation:

The equation balanced is:

2 FeCl₃ + 3 MgO → Fe₂O₃ + 3 MgCl₂

Equation balancing can be done by "trial and error" or by algebraic method.

In this way the equation is balanced on both sides having:

2 atoms of Fe, 6 of Cl, 3 of Mg and 3 of 0.

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Hii pls helpnme to write out the ionic equation ​
Oxana [17]

Answer:

CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)

Explanation:

According to this question, sodium carbonate reacts with sulfuric acid to form aqueous sodium sulfate, carbon dioxide and water. The balanced chemical equation is as follows:

Na2CO3(aq) + H2SO4(aq) → Na2SO4(aq) + CO2(g) + H2O(l)

- Next, split compounds that are aqueous into ions.

2Na+(aq) + CO32-(aq) + 2H+(aq) + SO42-(aq) → 2Na+(aq) + SO42-(aq) + CO2(g) + H2O(l)

- Next, we cancel out the spectator ions, which are ions that remain the same in the reactants and products side of a chemical reaction. The spectator ions in this equation are 2Na+(aq) and SO42-(aq).

CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)

- Hence, the balanced ionic equation is as follows:

CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)

3 0
3 years ago
What is glucose? How is it formed?​
Alik [6]
Glucose is a simple sugar with the molecular formula C6H12O6. It is a carbohydrate.
6 0
2 years ago
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Plz help ya' girl out!<br> Label the parts of whatever that is <br> Plz giving brainliest!
Burka [1]

Answer:

BRAINLIEST PLEASE!!!

A = Smooth Endoplasmic Reticulum

B = Vacuole

C = Mitochondria (Plural)

D = Nucleolus

E = Cell Wall

Explanation:

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2 years ago
U-235 undergoes many different fission reactions. For one such reaction, when U-235 is struck with a neutron, Ce-144 and Sr-90 a
Lostsunrise [7]

Explanation:

A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.

The given reaction is ^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + x^{1}_{0}n + y^{0}_{-1}\beta

Now, we balance the mass on both reactant and product side as follows.

         235 + 1 = 144 + 90 + (x \times 1) + (y \times 0)

           236 = 234 + x

            x = 236 -234

               = 2

So, now we balance the charge on both reactant and product side as follows.

              92 + 0 = 58 + 38 + (x \times 0) + (y \times -1)

                92 = 96 - y

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Thus, we can conclude that there are 2 neutrons and 4 beta-particles are produced in the given reaction.

Therefore, reaction equation will be as follows.

           ^{235}_{92}U + ^{1}_{0}n \rightarrow ^{144}_{58}Ce + ^{90}_{38}Sr + 2^{1}_{0}n + 4^{0}_{-1}\beta

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3 years ago
A student weighs out a 2.23 g sample of KF, transfers it to a 300 ml volumetric flask, adds enough water to dissolve it and then
densk [106]
Answer: i d8nt kn09.
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