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Advocard [28]
3 years ago
7

The reason radioactive isotopes can be followed through the steps of a chemical reaction or industrial process is that they

Chemistry
1 answer:
AnnyKZ [126]3 years ago
5 0
I think the correct answer from the choices listed above is option C. The reason radioactive isotopes can be followed through the steps of a chemical reaction or industrial process is that they do not react chemically as nonradioactive isotopes do. Hope this answers the question.
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What volume of 0.160 m li2s solution is required to completely react with 130 ml of 0.160 m co no3 2?
Over [174]
The  volume  of  0.160    m   Li2S  solution  required  to  completely  react  with  130 ml  of 0.160  CO(NO3)2  is calculated   as  below

write the  reacting  equation

Co(NO3)2 +  Li2S = 2LiNO3  +  COS

find the    moles  of CO(NO3)2  = molarity  x  volume

=  130 ml  x  0.160=20.8  moles

since the reacting moles between CO(NO3)2  to LiS  is   1:1  the  moles of LiS  is  also  20.8  moles

volume  of Lis  is  therefore =  moles of Lis/ molarity  of LiS

=  20.8/0.160 =  130 Ml
3 0
3 years ago
HElP PLS!! 20 points Which statement best describes a characteristic unique to renewable resources?
Fofino [41]

Answer:

renewable resources are abundant???

5 0
2 years ago
Read 2 more answers
140000 rounded to 3 sig gigs
attashe74 [19]
1.40E+5 (140000)
I believe this is right
8 0
3 years ago
275 g of a compound with the molecular formula ccl2f2 contains how many molecules of the compound
madreJ [45]
brainly.com/question/8581600#respond
3 0
2 years ago
If a car can go from 0 to 60 mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if its starting speed were 50
tangare [24]

Answer:

87.5 mi/hr

Explanation:

Because a = Δv / Δt (a = vf - vi/ Δt), we need to find the acceleration first to know the change in velocity so we can determine the final velocity.

vf = 60 mi/hr

vi = 0 mi/hr

Δt = 8 secs

a = vf - vi/ Δt

= 60 mi/hr - 0 mi/hr/ 8 secs

= 60 mi/hr / 8 secs

= 7.5 mi/hr^2

Now that we know the acceleration of the car is 7. 5 mi/hr^2, we can substitute it in the acceleration formula to find the final velocity when the initial velocity is 50 mi/hr after 5 secs.

vi = 50 mi/ hr

Δt = 5 secs

a = 7.5 mi/ hr^2

a = vf - vi/ Δt

7.5 = vf - 50 mi/hr / 5 secs

37.5 = vf - 50

87.5 mi/ hr = vf

7 0
3 years ago
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