False... The number of electrons in the outer shell of the atom of the element determines it's reactivity. <span />
Answer:
compound
Explanation:
because now there are one together
Answer:
When a substance gains or loses energy, its <u>temperature</u> or <u>state</u> changes. These two changes do <u>not</u> happen with respect to time; the temperature remains <u>the same</u> until the change of <u>state</u> is complete.
Explanation:
This statement is about energy and change of the state of the matter. By gaining or losing energy, the physical state of the matter can change into one another. Melting, freezing, condensation, evaporation, sublimation, and deposition are the processes that support to change the physical state of the matter. Change in state and change in the matter do not happen at the same time. A substance gains or loses energy to reach a specific temperature and remains constant until the physical change of matter is completed.
The electron-group arrangement of CO₃²⁻ is trigonal planar. The molecular shape is trigonal planar, and the ideal bond angle(s) is CO₃²⁻ is 120°
<h3>What is the molecular geometry of a compound?</h3>
The position of the compound's electrons and nuclei can be seen in the molecular geometry. It demonstrates how the form of the complex is created by the interaction of electrons and nuclei.
Here, according to the VSEPR theory, the shape of the carbonate ion is trigonal planar. The carbon will be in the center.
Thus, the electron-group arrangement and the shape of the carbonate ion are trigonal planar. The bond angle will be 120°.
To learn more about molecular geometry, refer to the link:
brainly.com/question/16178099
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Answer:
<h3>5.06282 × 10²⁴ molecules</h3>
Explanation:
The number of molecules of Ca2(SO3) can be found by using the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 8.41 × 6.02 × 10²³
We have the final answer as
<h3>5.06282 × 10²⁴ molecules</h3>
Hope this helps you