Question

Redox 1/2 reaction Cu(s) + 2 AgC2H3O2(aq) = Cu(C2H3O2)2(aq) + 2 Ag(s)

Answer 1

Explanation:

 Reaction:

              Cu  +     2AgC₂H₃O₂     →    Cu(C₂H₃O₂)₂    +     2Ag

The problem is to split the reaction into oxidation and reduction halves:

 The oxidation half is the sub-reaction that undergoes oxidation

  The reduction half is the one that undergoes reduction:

The ionic equation:

 Cu   +  2Ag⁺   +   2C₂H₃O₂⁻   →   Cu²⁺  +  2C₂H₃O₂⁻   +  2Ag

Oxidation half:

     Cu →  Cu²⁺ + 2e⁻

 

Reduction half:

    2Ag⁺ + 2e⁻ → 2Ag

C₂H₃O₂⁻ is neither oxidized nor reduced in the reaction.

learn more:

Oxidation state brainly.com/question/10017129

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