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luda_lava [24]
3 years ago
14

Which fluid is more dense, water or air?

Physics
1 answer:
pickupchik [31]3 years ago
6 0

Answer:

water

Explanation:

water is 1000 kg/m3 while air is 1.225 kg/m3

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De-Broglie postulated that the relationship, lambda=h/p is valid for relativistic particles. Find out the de-Broglie wavelength
Luda [366]

Given :

An electron with kinetic energy of 3 MeV.

To Find :

The de-Broglie wavelength for that electron.

Solution :

We know, de-Broglie wavelength for an electron with kinetic energy K.E is given by :

\lambda = \dfrac{h}{\sqrt{2m(K.E)}}

Putting all given values in above equation, we get :

\lambda = \dfrac{6.626\times 10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times 3\times 10^6 \times 1.6\times 10^{-19}}}\\\\\\\lambda = 7.089 \times 10^{-13} \ m

Hence, this is the required solution.

4 0
3 years ago
The Mass number of an element is the?
stepan [7]

Answer:

The mass number of an element is the number of protons plus neutrons.

Explanation:

The mass number of an element is the number of protons plus neutrons, so the correct answer is the option C.

4 0
3 years ago
Read 2 more answers
A 2.40 μC charge is subject to a 3.00 mN force due to an Electric Field. What is the magnitude of the Electric Field at the loca
Bezzdna [24]
<h2>Electric field at the location of the charge is 1250 N/C</h2>

Explanation:

Electric field is the ratio of force and charge.

Force, F = 3.00 mN = 3 x 10⁻³ N

Charge, q = 2.40 μC = 2.40 x 10⁻⁶ C

We have

                 E=\frac{F}{q}\\\\E=\frac{3\times 10^{-3}}{2.40\times 10^{-6}}\\\\E=1250N/C

Electric field at the location of the charge is 1250 N/C

4 0
3 years ago
How is light different than mechanical waves?
scoray [572]
Light waves don’t involve the motion of matter. Light waves are different from mechanical waves, because they can travel through a vacuum. Light waves are just one type of electromagnetic wave.
5 0
3 years ago
A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the
VLD [36.1K]

Answer:

0.75 NC⁻¹

Explanation:

Electric field intensity ( or strength of the electric field ) is the force per a 1 C charge,

So, Force (F) = Electric field intensity(E) × Charge (q)

                 F = E×q ⇒ q = F/E

                                      = 4.5×10⁻⁴/6×10⁻⁴ = 0.75 NC⁻¹

According to cool om's law electric fields are generated due to charges. When charges are same there is a repulsive force acted on both charges. When charges are opposite there is a attraction force acted  on both charges.

According to cool om's law,

F =G×q1×q2 / r²

F = force exerted of two charges

q1 , q2 = charges

r = distance between two charges

And also Electric field intensity is a vector which has a magnitude and direction both. Direction is depending on a charge and the sign of the charge

6 0
3 years ago
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