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3 years ago

What is a

Physics

1 answer:

LiRa [457]3 years ago

4 0

Answer:

I think there six points

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if a ball is released from a height 80cm how long would it take the ball to reach the ground when g= 10m per seconds

VLD [36.1K]

Answer:

The ball took 0.4 seconds

Explanation:

» From the second newton's equation of motion.

${ \boxed{ \tt{s = ut + \frac{1}{2} {gt}^{2} }}}$

s is displacement, s = 80cm, s = 0.8 meters
u is initial velocity, u = 0 [ from rest ]
g is 10 m/s²

${ \tt{0.8 = (0 \times t) + ( \frac{1}{2} \times 10 \times {t}^{2} )}} \\ \\ { \tt{0.8 = 5 {t}^{2} }} \\ { \tt{ {t}^{2} = 0.16 }} \\ { \tt{t = \sqrt{0.16} }} \\ \\ { \underline{ \underline{ \tt{ \: time = 0.4 \: seconds \: \: }}}}$

4 0

3 years ago

Read 2 more answers

So long as there are(is) ______ there is no movement.

patriot [66]

Answer:

answer is friction. MCQ A is answer

6 0

3 years ago

For each star, determine how its light would be shifted. Not all choices may be used, and some may be used more than once. A red

barxatty [35]

Answer:

Explanation:

To calculate the red shift you use the following formula:

$z=\frac{1+vcos\theta/c}{\sqrt{1-v^2/c^2}}-1$

\tetha: angle between the observer and the motion of the body

v: speed of the body

c: speed of light

for motion with angle 90° (transversal motion):

$z=\sqrt{\frac{c+v}{c-v}}-1$

- A red dwarf moving away from Earth at 39.1 km/s :

$z=\sqrt{\frac{3*10^8m/s+39.1*10^3m/s}{3*10^8m/s-39.1*10^3m/s}}-1=1.3*10^{-4}$

- A yellow dwarf moving transversely at 15.1 km/s (angle = 90°):

$z=\frac{1+0}{\sqrt{1-(15.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.27*10^{-9}$

- A red giant moving towards Earth at 23.3 km/s (angle = 0°):

$z=\frac{1+(23.3*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(23.3*10^3m/s)^2/(3*10^8m/s)^2}}-1=7.76*10^{-5}$

- A blue dwarf moving away from Earth at 25.9 km/s $z=\frac{1+(25.9*10^3m/s)/(3*10^8m/s)}{\sqrt{1-(25.9*10^3m/s)^2/(3*10^8m/s)^2}}-1=8.63*10^{-5}$

- A red dwarf moving transversely at 14.1 km/s

$z=\frac{1+0}{\sqrt{1-(14.1*10^3m/s)^2/(3*10^8m/s)^2}}-1=1.11*10^{-9}$

6 0

4 years ago

Rutherford proposed that...

geniusboy [140]

It is B because when he made the rays go through the atoms, a very small little of it created a repulsion which resulted in him proposing that there is a dense, positive nucleus in the atom while electrons are spinning around.

7 0

3 years ago

Using the rules for significant figures, what do you get when you subtract 13.52 from 55.3788?

andreyandreev [35.5K]

Answer:

55-13=42

Explanation:

your welcome :)

8 0

3 years ago