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In this problem we have the electric field intensity E:
E = 6.5 × newtons/coulomb
We have the magnitude of the load:
q = 6.4 × coulombs
We also have the distance d that the load moved in a direction parallel to the field 1.2 × meters.
We know that the electric potential energy (PE) is:
PE = qEd
So:
PE = (6.4 × )(6.5 ×
)(1.2 ×
)
PE = 5.0 x joules
None of the options shown is correct.
Answer:
Mass, m = 26.54kg
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
Where;
- Fnet is the net force
- Fapp is the applied force
- Fg is the force due to gravitation
<u>Given the following data;</u>
Net force, Fnet = 345
Acceleration, a = 3.2m/s²
<u>To find mass;</u>
Fnet = Fapp + Fg
Fnet = ma + mg
Fnet = m(a+g)
m = Fnet/(a+g)
We know that acceleration due to gravity, g = 9.8m/s²
Substituting into the equation, we have;
m = 345/(3.2 + 9.8)
m = 345/13
Mass, m = 26.54kg