D. The maximum electromotive force induced in the coil is determined as 3,200 V.
<h3>
Maximum electromotive force induced in the coil</h3>
emf(max) = NAB/t
where;
- N is number of turns
- B is magnetic field
- A is area of the coil
- t is time
Substitute the given parameters and solve for emf
emf(max) = (150 x 0.042 x 0.86) / (1.7 x 10⁻³)
emf(max) = 3,187.1 V
emf(max) ≈ 3,200 V
Thus, the maximum electromotive force induced in the coil is determined as 3,200 V.
Learn more about emf here: brainly.com/question/24158806
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Within the elastic limit of a solid material, the deformation (strain) produced by a force (stress) of any kind is proportional to the force. If the elastic limit is not exceeded, the material returns to it original shape and size after the force is removed, other it remains deformed or stretched.
Answer:
Explanation:
decreases while its rotational speed increases.
Answer:
11.25km/h²
Explanation:
Acceleration = Velocity / Time
Acceleration = 90 / 8
Acceleration = 11.25
She can climb 0.92 m without losing weight.
<u>Explanation</u>:
Gravitational potential energy is the energy consisting of the product of mass, gravity and height.
1 cal = 4184 J
140 cal = 585760 J
Energy = 585760 J, m = 65.0 kg = 65000 g, Efficiency = 20 %
GPE = mgh
where m represents the mass
g represents the gravity,
h represents the height.
585760 = 65000 9.8 h
h = 0.92 m.