a. The speed of the pendulum when it reaches the bottom is 0.9 m/s.
b. The height reached by the pendulum is 0.038 m.
c. When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
<h3>Kinetic energy of the pendulum when it reaches bottom</h3>
K.E = 100%P.E - 18%P.E
where;
K.E(bottom) = 0.82P.E
K.E(bottom) = 0.82(mgh)
K.E(bottom) = 0.82(1 x 9.8 x 0.05) = 0.402 J
<h3>Speed of the pendulum</h3>
K.E = ¹/₂mv²
2K.E = mv²
v² = (2K.E)/m
v² = (2 x 0.402)/1
v² = 0.804
v = √0.804
v = 0.9 m/s
<h3>Final potential energy </h3>
P.E = 100%K.E - 7%K.E
P.E = 93%K.E
P.E = 0.93(0.402 J)
P.E = 0.374 J
<h3>Height reached by the pendulum</h3>
P.E = mgh
h = P.E/mg
h = (0.374)/(1 x 9.8)
h = 0.038 m
<h3>when the pendulum stops</h3>
When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
Thus, the speed of the pendulum when it reaches the bottom is 0.9 m/s.
The height reached by the pendulum is 0.038 m.
When the pendulum no longer swing at all, all the kinetic energy of the pendulum has been used to overcome frictional force.
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Answer:
a) moves down
b) moves down
c) level remains same
Explanation:
Given that the anchor is initially on the floating boat.
a)
In this condition initially the the volume of water 
displaced is to balance its weight.
Now,
We've, the density of steel 
and the density of water 
When the anchor is dropped into water:
The volume of water displaced be 
which will be equal to the volume of anchor since it is immersed into it.
...................(1)
So the level of water falls when the anchor is dropped into water.
b)
Now, when the anchor is thrown on the ground the water has now less weight to balance so the water level falls down.
c)
When the cork on the from the boat is dropped into the water and it still floats then it must displace same amount of water, hence there should be no change in the water level.
Answer:
false 20 n x 0.32 m = 6.4 J
