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jolli1 [7]
3 years ago
5

HELLO ONCE MORE FRIENDS . PLEASE HELP ME.

Physics
2 answers:
tatuchka [14]3 years ago
5 0

Answer:

Do u want to talk?

Explanation:

nasty-shy [4]3 years ago
5 0

Answer:

You found answer yet?

Explanation:

You might be interested in
What term was used to describe the final digit
xxMikexx [17]

Answer:

Significant digits (also called significant figures or “sig figs” for short) indicate the precision of a measurement. A number with more significant digits is more precise. For example, 8.00 cm is more precise than 8.0 cm.

7 0
3 years ago
During the last shot of the game, the basketball goes from rest to 15 m/s and reaches the backboard in 0.41 s. What was the acce
Anna [14]

Answer: a= 37m

Explanation: V= 15 m/s (Velocity) t= 0.41s (time) formula: a= v/t

15 m/s / 0.41 (15 divided by 0.41) = 36.583m

There are 2 significant digits, 36, you look at the third digit, either round up or down in this case up to 36. a= 37m

5 0
3 years ago
Researchers want to see if college students are more committed to their fraternity after going through a hazardous hazing ritual
Mila [183]

Answer:

College student's commitment

Explanation:

The dependent variable is  the college students since it  is the variable we are going to measure as a result of the independent variable which is  the hazardous hazing ritual or non-hazardous hazing ritual.

8 0
3 years ago
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 81 N acts on
tensa zangetsu [6.8K]

Answer:

18 N

Explanation:

You have to do:

81 N: 9 ms2= x: 2 ms2

6 0
3 years ago
A sinusoidal wave of angular frequency 1,203 rad/s and amplitude 3.1 mm is sent along a cord with linear density 3.9 g/m and ten
kobusy [5.1K]

Answer:

18.7842493212 W

Explanation:

T = Tension = 1871 N

\mu = Linear density = 3.9 g/m

y = Amplitude = 3.1 mm

\omega = Angular frequency = 1203 rad/s

Average rate of energy transfer is given by

P=\dfrac{1}{2}\sqrt{T\mu}\omega^2y^2\\\Rightarrow P=\dfrac{1}{2}\sqrt{1871\times 3.9\times 10^{-3}}\times 1203^2\times (3.1\times 10^{-3})^2\\\Rightarrow P=18.7842493212\ W

The average rate at which energy is transported by the wave to the opposite end of the cord is 18.7842493212 W

7 0
3 years ago
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