Given:
Inductance, L = 150 mH
Capacitance, C = 5.00 mF
= 240 V
frequency, f = 50Hz
= 100 mA
Solution:
To calculate the parameters of the given circuit series RLC circuit:
angular frequency,
= 
a). Inductive reactance,
is given by:

b). The capacitive reactance,
is given by:

c). Impedance, Z = 

d). Resistance, R is given by:



e). Phase angle between current and the generator voltage is given by:




Answer:

Explanation:
Given data
Distance d=7.00 ft= 7*(1/3.281) =2.1336m
Initial velocity vi=0m/s
To find
Final velocity
Solution
From Kinematic equation we know that:

D is the correct answer, assuming that this is the special case of classical kinematics at constant acceleration. You can use the equation V = Vo + at, where Vo is the initial velocity, V is the final velocity, and t is the time elapsed. In D, all three of these values are given, so you simply solve for a, the acceleration.
A and C are clearly incorrect, as mass and force (in terms of projectile motion) have no effect on an object's motion. B is incorrect because it is not useful to know the position or distance traveled, unless it will help you find displacement. Even then, you would not have enough information to use a kinematics equation to find a.
Answer:
To convert inches to centimeters, use an easy formula and multiply the length by the conversion ratio.
Since one inch is equal to 2.54 centimeters, this is the inches to cm formula to conver
Explanation:
Answer:
(A). The work done by friction in crossing the patch is -637.98 J.
(B). The speed of skier is 10.57 m/s.
Explanation:
Given that,
Mass of skier = 62 kg
Speed = 6.5 m/s
Length = 3.50 m
Coefficient kinetic friction = 0.30
Height = 2.5 m
(A) we need to calculate the work done by friction in crossing the patch
Using formula of work done

Put the value into the formula


The work done by friction in crossing the patch is -637.98 J.
(B) we need to calculate the speed of skier
Using conservation of energy


Final potential energy is zero
So, 

Put the value into the formula



The speed of skier is 10.57 m/s.
Hence, (A).The work done by friction in crossing the patch is -637.98 J.
(B).The speed of skier is 10.57 m/s.