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3 years ago

The sum of two numbers is 200 and the two numbers in a ratio of 2.3. What is the larger number

Mathematics

1 answer:

dezoksy [38]3 years ago

8 0

Answer:

the larger number is 120

Step-by-step explanation:

sum of number = 200

total ratio = 2 + 3 = 5

ratio 1 = 200 ÷ 5 = 40

ratio 2 = 40 × 2 = 80

ratio 3 = 40 × 3 = 120

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Solve by the matrix method , x+y/5 -1=y-x

PIT_PIT [208]

10x - 4y = 5 (if it requires shorten)

Step-by-step explanation:

x + y/5 - 1 = y - x

<=> (5x + y - 1.5)/5 = 5(y - x)/5

<=> 5x + y - 5 = 5y - 5x

<=> 5x + 5x + y - 5y = 5

<=> 10x - 4y = 5

6 0

3 years ago

I need help on completing this

Allushta [10]

I don’t know I need points

7 0

3 years ago

Pleaseeee help ASAP it’s due today :(

Aleksandr [31]

Let, price increased by x times.

New price = 40 + ( 1 × x ) = 40 + x

It is given that for each $1 increase park loses 300 visitors.

Number of visitors = ( 24000 - 300x )

So, revenue is given by :

R = ( 24000 - 300x )( 40 + x ) ....1)

To finding critical point :

R'(x) = 0

-300( 40 + x ) + ( 24000 - 300x ) = 0 .....By product law

-12000 - 300x + 24000 -300x = 0

600x = 12000

x = 20

So, revenue is maximum at x = 20 .

Putting x = 20 in equation 1) , we get :

R = ( 24000 - 300x )( 40 + x )

R = [ 24000 - 300(20)][40 + 20 ]

R = $1080000

Therefore, park should charge $( 40 + 20 ) = $60 for maximising the revenue and maximum revenue is $10,80,000 .

Hence, this is the required solution.

5 0

3 years ago

Please answer this question I need this urgent Help meeeee

iren [92.7K]

Answer:

$\frac{s}{2t}$

Step-by-step explanation:

When you have exponents above a like term and they are being multiplied together, you add them.

For example:

$a^{x} *a^{y} = a^{x + y}$

So let's group like terms in the numerator:

$4r^{3} r^{-5} s^{-2} s^{-1}t$ We can add terms like in the example.

$4 r^{-2} s^{-3} t$

Let's rearrange the denominator.

$8r^{-2} s^{-4} t^{2}$

Now we have:

$\frac{4r^{-2} s^{-3}t}{8 r^{-2} s^{-4} t^{2} }$ Cancel like terms

4/8 = 1/2

$r^{-2} /r^{-2}$ = 1 So it cancels

$s^{-3} / s^{-4} = s^{-1}$ = s Since s is raised to the -1 it goes on top and becomes s.

$t / t^{2} = 1/t$

Now we combine everything back together:

$\frac{s}{2t}$

8 0

3 years ago

If f(x)=-2x-3 what is f(r+2) ?

fiasKO [112]

Answer:

$f(x) = - 2x - 3$

when x is r + 2 :

$f(r + 2) = - 2(r + 2) - 3 \\ = - 2r - 4 - 3 \\ = - 2r - 7 \\ \\ { \boxed{ \boxed{f(r + 2) = - 2r - 7}}}$

4 0

3 years ago