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3 years ago

Um i dnt understand maybe u can help me....

Mathematics

1 answer:

kirill115 [55]3 years ago

3 0

The answer is that because I just did that in class.

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I hope this helps you

7 0

3 years ago

Read 2 more answers

The function h(x)=1/x^2+1 is the result of the composition f(g(x)). If g(x) = x^2+1,what is f(x)? A f(x)=1/square root x B f(x)=

HACTEHA [7]

Answer:

Option B is correct

Step-by-step explanation:

Given: $h(x)=\frac{1}{x^2+1}$ is the result of the composition $f(g(x))$ .

Also, $g(x)=x^2+1$

To find: $f(x)$

Solution:

Take $f(x)=\frac{1}{x}$

Now check whether $h(x)$ is equal to $f(g(x))$ or not.

First find $f(g(x))$

$f(g(x))=f(x^2+1)=\frac{1}{x^2+1}$

Also, $h(x)=\frac{1}{x^2+1}$

Therefore,

$h(x)=f(g(x))$

So,

Option B is correct

3 0

4 years ago

Please help me solve this problem.

KatRina [158]

The square of the diagonal (d1) of the end face is
.. (d1)^2 = (3 in)^2 +(5 in)^2 = (9 +25) in^2 = 34 in^2

The square of the longest diagonal (d2) will be given by
.. (d2)^2 = (3x in)^2 +(d1)^2
.. = (9x^2 +34) in^2

So, the longest diagonal is
.. d2 = √(9x^2 +34) in

4 0

4 years ago

Four complex numbers form the vertices of a square in the complex plane. Three of the numbers are $-19 32i,$ $-5 12i,$ and $-22

Ugo [173]

If the three numbers of a square in the complex plane are $-19+32i,-5+12i and -22+15i$ , then the fourth complex number $-2+19i$ .

Given $-19+32i,-5+12i and -22+15i$ are three numbers.

Complex numbers are those numbers which extends the real numbers with an imaginary i. In this $i^{2}=-1$ . Major complex numbers are in the form a+ bi where a and b are real numbers.