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kicyunya [14]
3 years ago
5

In the Dorben Company and industrial engineer designed a workstation where the seeing task was difficult because of the size of

the components going into the assembly. The desired brightness was 100 fL and the workstation was painted a medium green with a reflectance of 50 percent. What illumination in foot-candles would be required at this workstation to provide the desired brightness? Estimated the required illumination if you repainted the workstation with a light cream paint. what is the luminance of a surface having a 50 % reflectance and a 4 fc illumination?
Physics
1 answer:
belka [17]3 years ago
7 0

Answer:

Illumination  = 200 fc

luminance =  2FL

Explanation:

given data

desired brightness = 100 fL

painted medium green reflectance = 50 percent

illumination = 4c

solution

we get here Illumination by using the formula that is

Illumination = luminance ÷ reflectance   ......................1

Illumination  = 100 fL ÷ 0.50

Illumination  = 200 fc

With light colored cream paint with a reflectance of 75%  the required illumination is 133 fc.

and

luminance will be

luminance = Illumination × reflectance = 4fc × 0.5 = 2FL

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Gravitational potential energy is related to–A. what an object is made of. B.an object’s motion.C. an object’s position.D. an ob
Bas_tet [7]

Answer:

The Answer is B because the material the object is made of, the position, or the color have absolutely nothing to do with gravitational potential energy

7 0
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You are working on a loading dock at UPS. You are instructed by your supervisor to move 20 boxes—each of which has a weight of 1
zhuklara [117]

Answer:

you have patience with me and I will call back tomorrow morning to discuss.

Explanation:

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3 years ago
Ac circuits have… A. Two current paths. B many current paths. C one current path. D two voltage paths
kow [346]
I would say…

B) they have many current paths
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3 years ago
A uniform plank of weight 100 N is 2000 mm long and rests on a support that is 400 mm from end E. At what distance from E must a
yan [13]

Answer:

the location of 160 N from end E is 25mm

Explanation:

given:

A uniform plank of weight 100 N is 2000 mm long

and rests on a support that is 400 mm from end E

find:

At what distance from E must a 160 N weight be placed in order to balance the plank?

                                                                      160 N

                                                                           |---x--->|

                                      100N                           \|/

======================||======================E

                                                            Δ---- 400mm---->|

|<----------------------------  2000mm   --------------------------->|

to determine the location of 160N load in order to balance the plank,

you have to take moment at support Δ.

note:

the 100 N is located at the center of a plank.

the distance of 100N from support = (2000 / 2) - 400 = 600mm

∑moment at Δ = 0

0 = -100 N (600mm) + 160 N (400-x)

0 = -60000 N.mm + 64000 N.mm - 160x N.mm

0 = 4000 - 160x

160x = 4000

x = 4000/160

x = 25 mm

therefore,

the location of 160 N from end E is 25mm

3 0
3 years ago
PLLLZ HELP Compare and contrast electric potential energy and electric potential difference? Please use 2 content related senten
masha68 [24]

The electric potential difference is the electric potential energy per unit charge

Explanation:

First of all, we define the concept of electric potential. The electric potential is a measure of the gradient of the electric field at a certain point of the space. The electric potential at a distance r from a positive charge of magnitude q is given by

V(r) = \frac{kq}{r}

where k is the Coulomb's constant.

Now we can define the electric potential energy and the electric potential difference:

  • Electric potential energy is the energy possessed by a charge due to the presence of an electric field. For a charge of magnitude q immersed in an electric field, its potential energy is given by U=qV, where V is the electric potential at the location of the charge.
  • The electric potential difference is simply the difference in electric potential between two points in the space. For instance, if the potential at point A is V(A) and the potential at point B is V(B), then the potential difference is \Delta V = V(A)-V(B)

The electric potential energy is also defined as the work done on a charge q moved through a potential difference of \Delta V. Consequently, the potential difference \Delta V represents the work per unit charge done, i.e. the work done when moving a unitary charge through a potential difference \Delta V.

Learn more about potential difference and current:

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brainly.com/question/12246020

#LearnwithBrainly

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