Answer:
The answer to your question is below
Explanation:
Data 1
mass 1 = 250
mass 2 = 250 kg
gravity constant = 6.67 x 10⁻¹¹ Nm²/kg²
distance = 8 m
Formula
Substitution
Result
F = 0.000000065 N
Data 2
mass 1 = 1000 kg
mass 2 = 1000 kg
distance = 5 m
Substitution
Result
F = 0.000002667 N
(a) 129.3 m
The motion of the rock is a projectile motion, consisting of two indipendent motions along the x- direction and the y-direction. In particular, the motion along the x- (horizontal) direction is a uniform motion with constant speed, while the motion along the y- (vertical) direction is an accelerated motion with constant acceleration downward.
The maximum height of the rock is reached when the vertical component of the velocity becomes zero. The vertical velocity at time t is given by
where
is the initial velocity of the rock
is the angle
t is the time
Requiring , we find the time at which the heigth is maximum:
The heigth of the rock at time t is given by
Where h=100 m is the initial heigth. Substituting t = 2.44 s, we find the maximum height of the rock:
(b) 44.1 m
For this part of the problem, we just need to consider the horizontal motion of the rock. The horizontal displacement of the rock at time t is given by
where
is the horizontal component of the velocity, which remains constant during the entire motion
t is the time
If we substitute
t = 2.44 s
Which is the time at which the rock reaches the maximum height, we find how far the rock has moved at that time:
(c) 7.58 s
For this part, we need to consider the vertical motion again.
We said that the vertical position of the rock at time t is
By substituting
y(t)=0
We find the time t at which the rock reaches the heigth y=0, so the time at which the rock reaches the ground:
which gives two solutions:
t = -2.69 s (negative, we discard it)
t = 7.58 s --> this is our solution
(d) 136.8 m
The range of the rock can be simply calculated by calculating the horizontal distance travelled by the rock when it reaches the ground, so when
t = 7.58 s
Since the horizontal position of the rock is given by
Substituting
and t = 7.58 s we find:
(e) (36.1 m, 128.3 m), (72.2 m, 117.4 m), (108.3 m, 67.4 m)
Using the equations of motions along the two directions:
And substituting the different times, we find:
Answer:
Explanation:
Given that
Number of particle =N
Equilibrium temperature= T
Side of cube = L
Gravitational acceleration =g
The kinetic energy of an atom given as
Where
Equilibrium temperature= T
Boltzmann constant =K
K =1.380649×10−23 J/K