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seraphim [82]
3 years ago
14

What would happen if you went through a black hole. I will give brainliest for a correct answer.

Physics
1 answer:
yawa3891 [41]3 years ago
8 0

Answer:

You would get spagettified. Streched into a very long noodle version of yourself.

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What is the equation for calculating the heat energy released during heating effect of electric current?
Nezavi [6.7K]
The heat energy released from a piece of wire or any other section of a circuit is:

Energy = (voltage between its ends) x (current through it) x (time it's been going)
5 0
3 years ago
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you start your bicycle ride at the top of a hill. you coast down the hill at a constant acceleration of 2.00 m/s^2. When you get
stiv31 [10]
198 meters I think, I could be wrong
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3 years ago
What is the difference between parallel and series​
DiKsa [7]

In a series circuit, the sum of the voltages consumed by each individual resistance is equal to the source voltage. ... In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component.

5 0
3 years ago
3. Atmospheric pressure is often given in units of millimeters of mercury. This refers to the height of a mercury column above t
gregori [183]

Answer:

101397.16 pa

Explanation:

The pressure recorded will be equal to pgh

Where p = density of mercury = 13.6x10^3 kg/m^ 3

g = acceleration due to gravity 9.81 m/s^2

h = height of mercury in the column = 760 mm = 760x10^-3 m

Pressure = 13.6x10^3 x 9.81 x 760x10^-3 = 101397.16 pa

6 0
3 years ago
In a wire with a 1.05 mm2 cross-sectional area, 7.93×1020 electrons flow past any point during 3.97 s. What is the current ????
34kurt

Answer:

The current in the wire is 31.96 A.

Explanation:

The current in the wire can be calculated as follows:

I = \frac{q}{t}

<u>Where</u>:

q: is the electric charge transferred through the surface

t: is the time      

The charge, q, is:

q = n*e

<u>Where</u>:

n: is the number of electrons = 7.93x10²⁰

e: is the electron's charge = 1.6x10⁻¹⁹ C

q = n*e = 7.93 \cdot 10^{20}*1.6 \cdot 10^{-19} C = 126.88 C

Hence, the current in the wire is:

I = \frac{126.88 C}{3.97 s} = 31.96 A

Therefore, the current in the wire is 31.96 A.

I hope it helps you!

3 0
3 years ago
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