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katen-ka-za [31]
3 years ago
6

So i need answers. Take your time its alright im not going to push it out. Thanks!

Chemistry
1 answer:
kirill115 [55]3 years ago
3 0
Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune
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Please can any one help me by answering this question!!+ignore my answer!,
den301095 [7]

I have posted the answetr in this picture.

8 0
3 years ago
What is the balanced form of the chemical equation shown below?
Tanzania [10]
B. 1, 1, 1, 2
Explanation:
You only need to balance the NaNO3 on the right. Since there is 2 NO3 on the left, you need to put a 2 in front of the NaNO3 on the right. Everything else is already balanced so the only coefficient needed is 2 in front of the NaNO3.
7 0
3 years ago
En el aire que respiramos y en el aire comprimido de los tanques de los buzos se encuentra, además de oxígeno, el gas nitrógeno
marysya [2.9K]

Answer: can someone please translate so i can answer.

Explanation:

sorry

7 0
3 years ago
Why do warm currents begin near the equator?
r-ruslan [8.4K]

Answer:

I would go with A

Explanation:

Because the earths equator is warmed by most direct rays of the sun, air a the equator is hotter than air further north or the south. The hotter air rises up at the equator and as colder air moves in to take its place, the wind begins to blow and push the ocean into waves and currents

5 0
3 years ago
A mixture of three gases has a pressure at 298 K of 1380 mm Hg. The mixture is analysed and is found to contain 1.27 mol CO2, 3.
enot [183]

Answer:

The partial pressure of Ar is 356.04 mm Hg (= 0.4685 atm)

Explanation:

<u>Step 1:</u> Data given

A mixture of three gases has a total pressure of 1380 mm Hg (=1.81579 atm) at 298 K

Moles of CO2 = 1.27 moles

Moles of CO = 3.04 moles

Moles of Ar = 1.50 moles

<u>Step 2:</u> Calculate total number of moles

Total number of moles = n(CO2)+ n(CO)+ n(Ar) = 1.27 mol+ 3.04 mol+ 1.50 mol = 5.81 moles

<u>Step 3:</u> Calculate mol fraction Ar

Mol fraction Ar = 1.50 mol/5.81 mol = 0.258

<u>Step 4</u>: Calculate partial pressure

1380 mm Hg * 0.258 moles Ar = 356.04 mm Hg = 0.4685 atm

The partial pressure of Ar is 356.04 mm Hg (= 0.4685 atm)

8 0
3 years ago
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