S + 2HNO3---> H2SO4 + 2NO
Answer:
1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.
Explanation:
Given data:
mass of cadmium = 6.35 g
Number of atoms of aluminum as 6.35 g cadmium contain = ?
Solution:
Number of moles of cadmium = 6.35 g/ 112.4 g/mol
Number of moles of cadmium = 0.06 mol
Number of atoms of cadmium:
1 mole = 6.022×10²³ atoms of cadmium
0.06 mol × 6.022×10²³ atoms of cadmium/ 1mol
0.36×10²³ atoms of cadmium
Number of atoms of Al:
Number of atoms of Al = 0.36×10²³ atoms
1 mole = 6.022×10²³ atoms
0.36×10²³ atoms × 1 mol /6.022×10²³ atoms
0.06 moles
Mass of aluminum:
Number of moles = mass/molar mass
0.06 mol = m/ 27 g/mol
m = 0.06 mol ×27 g/mol
m = 1.62 g
Thus, 1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.
Answer:
7.6 days
Explanation:
Radon is a radioactive element and Radon-222 is it's most stable isotope. The half-life of Radon-222 has been found to be approximately 3.8 days.
Let, the initial amount of the Rn-222 = 1 = A
Final amount = 
= A'
We will use the following relation for calculating time elapsed in the decay
Thus,
We can write is as,
Since the base in both sides are equal, powers can also be equal and thus,
So, t = 7.6 days
Answer:
Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer
Explanation:
The answer is reduction reaction. For every oxidation reaction that takes place, a reduction reaction must also happen, no reduction can occur without oxidation and vice versa. In redox reaction, atoms or ions undergo changes in the electronic structure, involving the transfer of electrons between reactants.
