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Licemer1 [7]
3 years ago
12

In the code snippet below, pick which instructions will have pipeline bubbles between them due to hazards.

Computers and Technology
1 answer:
denpristay [2]3 years ago
7 0

Answer:

b. lw $t4, 4($t0)

c. add $t3, $t5, $t4

Explanation:

Pipeline hazard prevents other instruction from execution while one instruction is already in process. There is pipeline bubbles through which there is break in the structural hazard which preclude data. It helps to stop fetching any new instruction during clock cycle.

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LAB: Parsing dates Complete main() to read dates from input, one date per line. Each date's format must be as follows: March 1,
Vladimir [108]

The python code which can be used to read dates from input, one date per line and each date's format must be as follows: March 1, 1990, is:

<h3>Python code</h3>

import datetime

inputs = []

result = []

#read the inputs

date = input()

inputs.append(date)

while not date == "-1":

 date = input()

 inputs.append(date)

#check if the input is in the correct format and convert it.

for date_text in inputs:

 try:

   date_text = datetime.datetime.strptime(date_text,"%d %B, %Y")

   result.append(date_text.strftime("%d/%m/%Y"))

 except ValueError:

   pass

   

print(*result, sep = "\n")

The above code would parse the string and extract the date. The split() method was used to break the input into tokens.

Read more about python programming here:

brainly.com/question/27666303

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6 0
2 years ago
Using the scenario below, answer the following questions:
4vir4ik [10]

Answer:

Here is code in java.

import java.util.*;

class Main

{

public static void main (String[] args) throws java.lang.Exception

{

   try{

         boolean flag=false;

         int total_mile=0;

         double avg_mile;

       // part 1, create and initialize array

       int inp[]={2,5,9,11,13,17,20,22,24,26};

       

       System.out.print("miles ran per week: ");

       // print the miles per week of train

       for(int x=0;x<10;x++)

       {

       System.out.print(inp[x]+" ");

       }

        System.out.println();

       //part 2, print the value of index 2 in the list

       System.out.println("value at index 2: "+inp[2]+" miles");

       //part 3, find length of array

       System.out.println("list length: "+inp.length);

     

       // part 4, calculate total mile and average

       for(int y=0;y<10;y++)

       {

       total_mile=total_mile+inp[y];

       }

       System.out.println("total miles ran: "+total_mile+" miles");

       

       avg_mile=total_mile/10.0;

       System.out.println("average no of miles ran= "+avg_mile+" miles");

       

     // part 5, check 4 exist in the list or not

       for(int k=0;k<10;k++)

       {

       if(inp[k]==4)

       {

       flag=true;

       break;

           }

       }

           if(flag)

           System.out.println("4 exist in the list.");

           else

            System.out.println("4 doesn't exists in the list.");  

       

   }catch(Exception ex){

       return;}

}

}

Explanation:

Create and initialize array with list value equals to 2 and maximum value 26. Print the miles of each week.Then find the value of miles at index 2 in the list.Next find the length of the array and print it.Calculate total miles ran of 10 weeks.Then calculate the average miles by dividing the total with 10. In the array, check 4 exist or not.

Output:

miles ran per week: 2 5 9 11 13 17 20 22 24 26                                                                            

value at index 2: 9 miles                                                                                                  

list length: 10                                                                                                            

total miles ran: 149 miles                                                                                                

average no of miles ran= 14.9 miles                                                                                        

4 doesn't exists

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3 years ago
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You are troubleshooting a mobile device that will not pair with a Bluetooth headset. The device was functioning properly with th
bulgar [2K]

Answer:

B. Replace the Bluetooth headset with a new pair.

Explanation:

Since all other mobile devices, after receiving the "corporate-wide" OS update, aren't having issues with pairing with Bluetooth headsets, we can safely conclude that the OS update isn't the issue.

To find out if the Bluetooth headset is not the culprit, we can try to pair the mobile device with a different headset. If it pairs correctly, then we can conclude that the old Bluetooth headset might have a fault, or it might need to be disconnected/forget from the device and paired gain.

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3 years ago
What is self management.​
OLEGan [10]

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