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My name is Ann [436]
3 years ago
10

Identify each sequence below as geometric, arithmetic, or neither.

Mathematics
1 answer:
vitfil [10]3 years ago
8 0
1) arithmetic
2) neither
3) geometric
4) geometric
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Jenny's lunch account has $10 in it. She buys lunch three days in a row and spends $2.50, $2, and $2.75. On the fourth day, she
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10-(2.5+2+2.75)+10-3 = 9.75
7 0
1 year ago
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4x + y = 3 -2x + 3y = -19 what's the solution plz help
Rainbow [258]

The solution to given system of equations is x = 2 and y = -5

<em><u>Solution:</u></em>

<em><u>Given the system of equations are:</u></em>

4x + y = 3 ---------- eqn 1

-2x + 3y = -19 ---------- eqn 2

We have to find the solution to above system of equations

<em><u>We can solve the system by substitution method</u></em>

From eqn 1,

4x + y = 3

Isolate y to one side

y = 3 - 4x ----------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

-2x + 3(3 - 4x) = -19

-2x + 9 - 12x = -19

Combine the like terms

-14x = -19 - 9

-14x = -28

Divide both sides of equation by -14

<h3>x = 2</h3>

<em><u>Substitute x = 2 in eqn 3</u></em>

y = 3 - 4(2)

y = 3 - 8

<h3>y = -5</h3>

Thus the solution is x = 2 and y = -5

5 0
3 years ago
Please help, this chapter was on derivatives...
Usimov [2.4K]
<h3>Answer:  ds/dt = 11</h3>

================================================

Work Shown:

Before we can use derivatives, we need to find the value of s when (x,y) = (15,20)

s^2 = x^2+y^2

s^2 = 15^2+20^2

s^2 = 225+400

s^2 = 625

s = sqrt(625)

s = 25

-----------

Now we can apply the derivative to both sides to get the following.  Don't forget to use the chain rule.

s^2 = x^2 + y^2

d/dt[s^2] = d/dt[x^2 + y^2]

d/dt[s^2] = d/dt[x^2] + d/dt[y^2]

2s*ds/dt = 2x*dx/dt + 2y*dy/dt

2(25)*ds/dt = 2(15)*5 + 2(20)*(10)

50*ds/dt = 150 + 400

50*ds/dt = 550

ds/dt = 550/50

ds/dt = 11

-----------

Side note: The information t = 40 is never used. It's just extra info.

8 0
3 years ago
PQ⊥PS , m∠QPR=7x−9, m∠RPS=4x+22<br> Find : m∠QPR
emmainna [20.7K]

Given:

It is given that,

PQ ⊥ PS and

∠QPR = 7x-9

∠RPS = 4x+22

To find the value of ∠QPR.

Formula

As per the given problem PR lies between PQ and PS,

So,

∠QPR+∠RPS = 90°

Now,

Putting the values of ∠RPS and ∠QPR we get,

7x-9+4x+22 = 90

or, 11x = 90-22+9

or, 11x = 77

or, x = \frac{77}{11}

or, x = 7

Substituting the value of x = 7 in ∠QPR we get,

∠QPR = 7(7)-9

or, ∠QPR = 40^\circ

Hence,

The value of ∠QPR is 40°.

3 0
3 years ago
Find a parametrization r ( t ) r(t) of the line through the origin whose projection on the x y - xy- plane is a line of slope 8
ankoles [38]

Answer:

please check the attached file for the answer

Step-by-step explanation:

the explanation is in the attached file

8 0
3 years ago
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