Answer:
\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}
Explanation:
Hello,
The suitable differential equation for this case is:
As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:
Of course, 
.
Now, since the volume of a cone is 
and the ratio 
or 
, the volume becomes:
We proceed to its differentiation:
Then, we compute 
Finally, at h=2:
Best regards.
In this item, I supposed, that we are determine the molar fraction of oxygen and carbon dioxide in the sample. This can be done by dividing their respective partial pressures by the total pressure of the sample.
O2 : mole fraction = (100.7 mmHg) / (763.00 mmHg) = 0.13
CO2 : mole fraction = (33.57 mmHg) / (763.00 mmHg) = 0.044
Answers: O2 = 0.13
CO2 = 0.044
The answer is a change in internal energy causes work to be done and heat to flow into the system.
<u>Explanation:</u>
Boyle's law says, PV=RT
- Here P represents the pressure, V represents the volume and T represents the temperature. R is a constant. The volume of an ideal gas is inversely proportional to its pressure if the temperature is constant.
- When a bubble is present in deep water it has water pressure and atmospheric pressure. Then the Volume increases when water pressure raises which is proportional to the depth reduces.
- But we should not finalize the volume of the bubble will be four-time as great as at the top than the bottom. if the bottom of the lake is at four atmospheres, the temperature will not be equal to the top.
- If the bubble travels from the bottom to the top or vice-versa, it's going to lose or gain heat in a way that must be quite hard to measure.
El Niño refers to the above-average sea-surface temperatures that periodically develop across the east-central equatorial Pacific. It represents the warm phase of the ENSO cycle. La Niña refers to the periodic cooling of sea-surface temperatures across the east-central equatorial Pacific.
(weather patterns not girl and boy)
