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mart [117]
2 years ago
12

Which option identifies all the bonds broken during this chemical reaction?

Chemistry
2 answers:
Tresset [83]2 years ago
7 0

Answer:

the bond b/w oxygen and hydrogen atom

yaroslaw [1]2 years ago
5 0

Answer: A, the bonds between the two hydrogen atoms and between the two oxygen atoms.

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5. 16.3 g of NaCl is dissolved in water to make 1.75 L of solution. What is the molarity of this solution? A 0.159 M B 0.278 M C
ira [324]

Answer: The molarity of this solution is 0.159 M.

Explanation:

Given: Mass of solute = 16.3 g

Volume = 1.75 L

Number of moles is defined as the mass of substance divided by its molar mass.

Hence, moles of NaCl (molar mass = 58.44 g/mol) ar calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{16.3 g}{58.44 g/mol}\\= 0.278 mol

Molarity is the number of moles of a substance present in a liter of solution.

So, molarity of the given solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.278 mol}{1.75}\\= 0.159 M

Thus, we can conclude that the molarity of this solution is 0.159 M.

5 0
3 years ago
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Hoochie [10]

Answer:

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Explanation:

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4 0
3 years ago
The change of state from a gas to a liquid is called?
evablogger [386]
<span>This change is called BOILING.</span>
8 0
3 years ago
Read 2 more answers
How can you describe waves by their properties?
Molodets [167]

Explanation:

There are many properties that scientists use to describe waves. They include amplitude, frequency, period, wavelength, speed, and phase. Each of these properties is described in more detail below. When drawing a wave or looking at a wave on a graph, we draw the wave as a snapshot in time.

4 0
3 years ago
1000 cm3 of hydrogen gas (hydrogen molecules, H2) contains x number of molecules at room temperature and pressure. Determine the
Gekata [30.6K]

Answer: Number of atoms in 500cm^3 of radon gas (radon atoms) at the same temperature and pressure is \frac{x}{2}

Explanation:

According to avogadro's law, volume of a gas is directly proportional to the number of moles present when temperature and pressure is constant.:

\frac{V_1}{n_1}=\frac{V_2}{n_2}

V_1 = Volume of the hydrogen gas = 1000cm^3

n_1 =  moles of hydrogen gas = \frac{xmolecules}{6.023\times 10^{23}molecules}

V_2=  Volume of the radon gas =500cm^3

n_1 =  moles of radon gas = ?

\frac{1000}{\frac{x}{6.023\times 10^{23}}}=\frac{500}{\frac{y}{6.023\times 10^{23}}}

y=\frac{x}{2}

Thus the number of atoms in 500cm^3 of radon gas (radon atoms) at the same temperature and pressure is \frac{x}{2}

7 0
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