-OH is elctron donating -C=-N is electron withdrawing -O-CO-CH3 is electron withdrawing -N(CH3)2 is electron donating -C(CH3)3 is electron donating -CO-O-CH3 is electron withdrawing -CH(CH3)2 is electron donating -NO2 is electrong withdrawing -CH2

8 0

4 years ago

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

Andrews [41]

The given question is incomplete. The complete question is as follows.

A certain liquid has a normal boiling point of $124.2^{o}C$ and a boiling point elevation constant $k_{b} = 0.62 ^{o}C kg mol^{-1}$ . A solution is prepared by dissolving some sodium chloride (NaCl) in 6.50 g of X. This solution boils at $127.4^{o}C$ . Calculate the mass of NaCl that was dissolved. Round your answer to significant digits.

Explanation:

As per the colligative property, the elevation in boiling point will be as follows.

T = boiling point of the solution =

$T_{o}$ = boiling point of the pure solvent = $124.2^{o}C$

$K_{b}$ = elevation of boiling constant = $0.62 ^{o}C kg mol^{-1}$

We will calculate the molality as follows.

molality = $\frac{\text{maas of solute}}{\text{molar mass of solute}} \times \frac{1000}{\text{mass of solvent in g}}$

i = vant hoff's factor

As NaCl is soluble in water and dissociates into sodium and chlorine ions so i = 2.

Putting the given values into the above formula as follows.

$T - T_{o} = i \times K_{b} \times \text{molality of solution}$

$(127.4 - 124.2)^{o}C = 2 \times 0.62 \times \frac{m}{60} \times \frac{1000}{650}$

m = 100 g

Therefore, we can conclude that 100 g of NaCl was dissolved.

3 0

3 years ago

Explain the difference between an organic and inorganic compound.

galben [10]

The most common differentiation to help distinguish between organic and inorganic compounds used to be the fact that organic compounds result from the activity of living beings, whereas inorganic compounds are either the result of natural processes unrelated to any life form or the result of human experimentation in the laboratory.<span><span /></span>

8 0

3 years ago

Read 2 more answers

Calcium metal is obtained by direct electrolysis of molten cacl2. if a metallurgical electrolysis apparatus operates at 28.70 a,

ser-zykov [4K]

There is 1 mole of electrons = 96500C and Ca = 40
Ca2+ + 2e --->Ca
Base on the formula above it means that there are 2 moles of electrons to produce 1 mole of calcium.

96500C x 2 = 193000C

193000C electricity produce 40g Calcium

Coulombs = Amps x seconds (28.70A for 12 hours)
= 28.70A x 12 x 60 x 60 C
= 1 239 840 C

This amount of electricity will produce

=1239840 / 193000 x 40g Calcium
= 6.42 x 40 g Calcium
= 256.96 g

So there will be 256.96g of Calcium metal that will be produced in 12 hours.

6 0

3 years ago