Al S
1) <u> 35.94 </u> =1.33111 <u> 64.06 </u> = 2.001875
27 32
2) = <u> 1.33111 </u> = <u> 2.001875 </u>
1.33111 1.33111
3) = ( 1 ) × 2 = ( 1.5 ) ×2
4) = 2 = 3
Empirical Formula = Al2S3
1) Divide the percentage given in question by the Relative Atomic Mass (RAM)
of the given elements.
2) When you find the answers of the first part of question, divide these once again but this time, by the lowest number you found in part 1.
3) and 4) Write down the values. If you get a decimal which is in between 0.3-0.7 (including the 0.3 and 0.7), you cannot make it a whole number by rounding of. Therefore, multiply the decimal with a whole number until you get a whole number as your answer. In this question, when you multiply 1.5 by 2, the answer is 3 which is a whole number. Multiply the other whole number by the same number as that you multiplied for 1.5. And use these numbers in part 4 to make the empirical formula which is Aluminium Sulfide (Al2S3)
Hope this helps you :)))
Please give this a brainliest
The answer is c.
Elements on the left side of the table are metals, such as sodium, lithium, potassium, etc.
Elements on the right side are non metals, such as Chlorine, Fluorine, Bromine, etc.
ethane is the compound of the answer you are asking help
Volume of O2 : 168 L
<h3>Further explanation</h3>
Given
Reaction
2 KClO3 (s) → 2 KCl (s) + 3 O2 (g)
5 moles of KCIO3
Required
volume of O2
Solution
From the equation, mol O2 :
= 3/2 x moles KClO3
= 3/2 x 5 moles
= 7.5 moles
Assumed at STP( 1 mol = 22.4 L) :
= 7.5 x 22.4 L
= 168 L
