The heat being released is calculated by multiplying the amount of NaOH used for making the solution. We are given a delta H that is equal to -445.1 kJ / mol. This value is per mole NaOH. Calculation is as follows:
-445.1 kJ / mol NaOH (1.0 g NaOH ) ( 1 mol NaOH / 40 g NaOH ) = -11.1 kJ
Answer: decreases
Explanation:
Atomic radius in a period from left to right decreases due to increase in nuclear charge.
On moving from left to right, electrons are getting added in outer shell and no of protons also increased which results increase in nuclear charge. Increased nulcear charge holds the electrons tigthly hence electrons moves close to nucleus. So radius decreases.
Answer: formic acid
Explanation:
HCOOH is the structural formula for the compound commonly known as formic acid.
According to the international union of pure applied chemist (IUPAC), it is named methanoic acid, and represent the first member of the alkanoic acids.
Thus, examples of alkanoic acids are
- formic acid (HCOOH)
- Acetic acid (CH3COOH)
- Propanoic acid (CH3CH2COOH) etc
0.499 mol
Explanation: M(CaC2) = 64.1 g/mol, n= m/M = 32.0 g/ 64.1 g/ mol= 0.499 mol
Amount of Calcium hydroxide Is same
