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rodikova [14]
3 years ago
10

How do elements on the right side of the periodic table differ from elements on the left side of the table?

Chemistry
1 answer:
lozanna [386]3 years ago
4 0

The answer is c.


Elements on the left side of the table are metals, such as sodium, lithium, potassium, etc.


Elements on the right side are non metals, such as Chlorine, Fluorine, Bromine, etc.

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Please check this for me?
kolbaska11 [484]
The answer is 
<span>2PbS(s) + 3O2(g) = 2PbO(s) + 2SO2(g)

Your answer is not yet balanced because you have 3 oxygen atoms. it should be balanced by multiplying both side by 2 such as the balanced equation I made. To check it, I will explain why your answer is not yet balanced.

check: (from your equation)
</span> 1-Pb-1
 1-S-1
2 -O-3
the difference between the reactant and the product of Oxygen will prove that it is not yet balanced.

If you use 2PbS(s) + 3O2(g) = 2PbO(s) + 2SO2(g), to check it:
2-Pb-2
 2-S-2
6 -O-6
then this is now balance
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3 years ago
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Answer:

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I hope this helps.
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