1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
rodikova [14]
3 years ago
10

How do elements on the right side of the periodic table differ from elements on the left side of the table?

Chemistry
1 answer:
lozanna [386]3 years ago
4 0

The answer is c.


Elements on the left side of the table are metals, such as sodium, lithium, potassium, etc.


Elements on the right side are non metals, such as Chlorine, Fluorine, Bromine, etc.

You might be interested in
In May 2016, William Trubridge broke the world record in free diving (diving underwater without the use of supplemental oxygen)
Maru [420]

Answer:

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 3.6 L  

V₂ = ?

P₁ = 1.0 atm

P₂ = 13.3 atm (From correct source)

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{1.0\ atm}\times {3.6\ L}={13.3\ atm}\times {V_2}

{V_2}=\frac{{1.0}\times {3.6}}{13.3}\ L

{V_2}=0.27\ L

The volume that this same amount of air will occupy in his lungs when he reaches a depth of 124 m is - 0.27 L.

7 0
3 years ago
What type of reaction is required to bind two molecules of glycine together and release a molecule of water?​?
bulgar [2K]
<span>The glycine molecules can bind together and release a molecule of water by the process of condensation. Water would then be considered a by-product of the reaction. Condensation can also be seen when water in the air touches a container filled with cold liquid and you see water drops on the side of the glass.</span>
8 0
2 years ago
5. What is metallic bonding?<br> 6. Why are metals shiny?
cricket20 [7]

Answer:

Metallic bonding is found in metals and their alloys. When the atoms give up their valence electrons, they form ions. These ions are held together by the electron cloud surrounding them. Metals are shiny because they have a lot of free (i.e. delocalized) electrons that form a cloud of highly mobile negatively charged electrons on and beneath the smooth metal surface in the ideal case. ... In the absence of any external EM field, the charges in the plasma are uniformly distributed within the metal.

Explanation:

In metallic bonding, the electrons are “surrendered” to a common pool and become shared by all the atoms in the solid metal.

4 0
3 years ago
Please somebody give me the answers
RSB [31]

Answer:

1. 9.4 grams of methane produce<u> 25.85</u> grams of CO2

2.Grams of water produced = <u>11.81 grams</u>

3.Mass of Methane produced by 10.1 gram of O2 = <u>2.52 grams</u>

4.Amount of methane consumed = <u>46.9 grams</u>

5. Grams of Co2 produced =<u> 8.32 grams</u>

<u></u>

Explanation:

Molar masses :

Methane = CH4 = mass of C + 4x (mass of H)

CH4 = 12 +4(1) = 16 grams

<u>1 mole of CH4 = 16 gram</u>

Oxygen O2 = 2 x (mass of O) = 2x(16) = 32 gram (1 mole of O2 =32 gram)

Carbon Dioxide =CO2 = mass of C + 2(mass of O)

= 12 + 2(16)

= 44 grams <u>(1 mole of CO2 = 44 gram )</u>

Water = H2O = 18 grams ( 1 mole of H2O = 18 gram)

1 mole of each molecule is equal to their molar masses

The balanced equation is :

1CH_{4}(g)+2O_{2}\rightarrow 1CO_{2}+2H_{2}O(l)

According to Stoichiometry :

1 mole of CH4 = 2 Mole of O2 = 1 mole of CO2 = 2 mole of H2O

1. From the equation ,

1 mole of methane produce  =1 mole of CO2

16 gram of methane = 44 gram of CO2

1 gram of methane =

\frac{44}{16} gram of CO2

9.4 gram of CH4 =

\frac{44}{16}\times 9.4 gram of CO2

= 25 .85 gram of CO2

2.

2 mole of O2 produces = 2 mole of H2O(water)

1 mole of O2 produces = 1 mole of H2O

32 gram of O2 = 18 gram of water

1 gram of O2 =

\frac{18}{32}

21 gram of O2 =

\frac{18}{32}\times 21

11.81 gram of water

3. 1 mole of CH4 = 2 mole of O2

16 gram of CH4 = 2(32)  = 64 grams of O2

64 gram of O2 needs = 16 grams of CH4

1 gram of O2 needs =

\frac{16}{64}

10.1 gram of O =

\frac{16}{64}\times 10.1 of CH4

= 2.52 gram

4.

1 mole of CO2 is produced from = 1 mole of CH4

44 gram of CO2 is produced from 16 gram of CH4

1 gram CO2 =

\frac{16}{44} gram of CH4

129 gram of CO2 =

\frac{16}{44}\times 129 gram of CH4

= 46.90 grams

5.

2 mole of O2  produce = 1 mole of CO2

2x 32 gram of O2 = 44 gram of CO2

1 gram of O2 =

\frac{44}{64} of CO2

12.1 gram of O2 produce=

\frac{44}{64}\times 12.1 of CO2

= 8.318 gram

Note : Write the quantity give on left side of "="

write the substance asked on right side of "="

8 0
3 years ago
LAB: predicting products
kondor19780726 [428]

Answer:

1) synthesis MgI2

2) double replacement CuS + (HCl)2

3) double replacement, not sure ab the formula sorry

4 0
2 years ago
Other questions:
  • Why do your feet feel cooler on a tile floor than on a warm rug? A. The tile is a poor conductor. B. The rug is a good conductor
    15·2 answers
  • Volume of carbon dioxide gas evolved at STP by heating 7.3 gram of Mg(Hco3)2 will be​
    9·2 answers
  • How many times more acidic is a solution with a pH of 2 than<br> one with a pH of 4?
    12·1 answer
  • We can determine the potential of a single electrode by:____________.
    8·1 answer
  • What does electronegativity mean?
    5·1 answer
  • HURRY PLEASE
    11·1 answer
  • 40 POINTS!! If all of the water is removed from a one-mole sample of Ba(OH)2·8H2O, by how many grams will the mass of the sample
    14·1 answer
  • In a chemical reaction, the mass of the reactants is 13.3 grams. Which of the following could represent the mass of the products
    7·2 answers
  • The mass of an object is measured in _____.
    7·2 answers
  • you wish to prepare an hc2h3o2 buffer with a ph of 5.44. if the pka of the acid is 4.74, what ratio of c2h3o2-/hc2h3o2 must you
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!