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oee [108]
3 years ago
12

What is Newton's gravitational constant ? write down its value and si unit.​

Physics
1 answer:
Irina18 [472]3 years ago
6 0
Answer: 6.67 x 10^-11 m^3•kg^-1•s^-2
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Why would the measurements have to take place around the same time every day
bixtya [17]
It is vital to take measurements at the same time everyday to determine the natural cycle, this will show the numbers on a regular basis. It is important because this will be basis of any action that needs to be taken. If it's not taken at the same time, it may disrupt the correct result or change the expected outcome.
5 0
3 years ago
a lamp hangs from the ceiling at the height of 2.9 m. if the lamp breaks and falls to the floor what is its impact speed
nydimaria [60]
This is a problem that can be solved using free-fall motion analysis. Since the displacement (2.9m) is given, we can use the following equation to solve for the impact speed:

V^2 = 2gh

V = sqrt (2*9.8*2.9)
V = 7.54 m/s
5 0
4 years ago
A sound source of frequency f moves with constant velocity (less than the speed of sound) through a medium that is at rest. A st
ANTONII [103]

Answer:

The correct answer is d

Explanation:

In this exercise they ask us which statement is correct, for this we plan the solution of the problem, this is a Doppler effect problem, it is the frequency change due to the relative speed between the emitter and the receiver of sound.

The expression for the Doppler effect of a moving source is  

f ’= (v / (v- + v_s) f  

From this expression we see that if the speed the sound source is different from zero feels a change in the  frequency.

The correct answer is d

7 0
3 years ago
What force was applied to an object if 35 J of work was done and the object moved 7 m? Show your work.
ahrayia [7]

Answer:

5 N

Explanation:

The work done by a force on an object is (assuming that the direction of the force is parallel to the displacement of the object):

W=Fd

where

F is the magnitude of the force

d is the displacement of the object

In this problem, we know that:

W = 35 J is the work done

d = 7 m is the displacement of the object

Therefore, we can re-arrange the equation to calculate the force applied:

F=\frac{W}{d}=\frac{35 J}{7 m}=5 N

8 0
3 years ago
When running a 100 meter race Donald reaches his maximum speed when he is 40 meters from the starting line, and 7 seconds have e
Slav-nsk [51]

Answer:

Part a)

v_{max} = 7 m/s

Part b)

d = 7 \times 3 = 21 m

Part c)

d = 61 m

Part d)

d = 50.5 m

Explanation:

As we know that he start from rest and moves with uniform acceleration

so here we can say that

d = v\Delta t

as we know here that he move with uniform speed from t = 7 to t = 11

So we will have

68 - 40 = v(11 - 7)

28 = 4 v

v_{max} = 7 m/s

Part b)

If Donald runs for 3 s after reaching his maximum speed

So here distance moved by Donald

d = v t

d = 7 \times 3 = 21 m

Part c)

Distance of Donald from start line is given as

d = 40 + 21

d = 61 m

Part d)

Distance from start line after t = 8.5 s

d = 40 + vt

d = 40 + (7)(1.5)

d = 50.5 m

5 0
3 years ago
Read 2 more answers
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