1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnom [1K]
3 years ago
9

Tarzan, whose mass is 103 kg, is hanging at rest from a tree limb. Then he lets go and falls to the ground. Just before he lets

go, his center of mass is at a height 2.4 m above the ground and the bottom of his dangling feet are at a height 1.5 above the ground. When he first hits the ground he has dropped a distance 1.5, so his center of mass is (2.4 - 1.5) above the ground. Then his knees bend and he ends up at rest in a crouched position with his center of mass a height 0.3 above the ground.
Required:
Consider the real system. What is the net change in internal energy for Tarzan from just before his feet touch to the ground to when he is in the crouched position?
Physics
1 answer:
Anettt [7]3 years ago
6 0

Answer:

   v₀ = 60.38 mi / h

With this stopping distance, the starting speed should have been 60.38 mi/h, which is much higher than the maximum speed allowed.

Explanation:

For this exercise let's start by using Newton's second law

Y axis

        N-W = 0

        N = W

X axis

         fr = m a

the expression for the friction force is

         fr = μ N

we substitute

        μ mg = m a

        μ g = a

calculate us

         a = 0.620  9.8

         a = 6.076 m / s²

now we can use the kinematics relations

          v² = v₀² - 2 a x

suppose v = 0

          v₀ = \sqrt{2ax}Ra 2ax

let's calculate

         v₀ = \sqrt{2 \ 6076 \ 60}

         v₀ = 27.00 m / s

let's slow down to the english system

          v₀ = 27.0 m / s (3.28 ft / 1m) (1 mile / 5280 ft) (3600s / 1h)

          v₀ = 60.38 mi / h

With this stopping distance, the starting speed should have been 60.38 mi/h, which is much higher than the maximum speed allowed.

You might be interested in
What would happen to a satellite if it’s orbit speed was reduced by half? Also how about if it doubled?
weeeeeb [17]

For finding the orbital speed of the satellite we can say that the centripetal force for the circular motion of satellite is provided by the gravitational force of earth

so here we can say

F_g = \frac{mv^2}{r}

\frac{GMm}{r^2} = \frac{mv^2}{r}

now we will have

v = \sqrt{\frac{GM}{r}}

now here we will say that orbital speed of the satellite is inversely depends on the orbital radius

<em>So here if orbital speed is half then as per above relation we can say that orbital distance will become four times</em>

<em>Also we can say that if orbital speed is double then orbital distance will become one fourth of initial distance.</em>

7 0
3 years ago
Why do astronauts muscles weaken?
Pavlova-9 [17]
They work on a weightless planet, therefore they have very little muscle control since they float in space !!
3 0
3 years ago
In which part of the scientific method would you make a prediction?
max2010maxim [7]
<span>In which part of the scientific method would you make a prediction?

hypothesis



A statement that explains an observation and is supported by data is a

scientific theory



In which part of the scientific method would you record your observations?

experiment



A scientific statement that describes an observation but does not explain the observation is

a scientific law

</span>
4 0
3 years ago
A 0.17kg ball rolls at 0.75m/s to the right on a frictionless surface and collides with a 0.17kg ball rolling to the left at 0.6
mario62 [17]

Both momentum and kinetic energy are conserved in elastic collisions (assuming that this collision is perfectly elastic, meaning no net loss in kinetic energy)

To find the final velocity of the second ball you have to use the conversation of momentum:

*i is initial and f is final*

Δpi = Δpf

So the mass and velocity of each of the balls before and after the collision must be equal so

Let one ball be ball 1 and the other be ball 2

m₁ = 0.17kg

v₁i = 0.75 m/s

m₂ = 0.17kg

v₂i = 0.65 m/s

v₂f = 0.5

m₁v₁i + m₂v₂i = m₁v₁f + m₂v₂f

Since the mass of the balls are the same we can factor it out and get rid of the numbers below it so....

m(v₁i + v₂i) = m(v₁f + v₂f)

The masses now cancel because we factored them out on both sides so if we divide mass over to another side the value will cancel out so....

v₁i + v₂i = v₁f + v₂f

Now we want the final velocity of the second ball so we need v₂f

so...

(v₁i + v₂i) - v₁f = v₂f

Plug in the numbers now:

(0.75 + 0.65) - 0.5 = v₂f

v₂f = 0.9 m/s


8 0
3 years ago
WILL BE BRAINLIEST <br> HELP!!!
ivolga24 [154]

Answer:

(8.0÷6.0)×10[(-2)-(-3)]

6 0
3 years ago
Other questions:
  • An example of a source would be _____.
    15·2 answers
  • On a cloudless day, the sunlight that reaches the surface of the earth has an intensity of about 1.40 × 10 3 1.40×103 W/m². What
    5·1 answer
  • An object moves in uniform motion at 25 m/s and takes 1.0 seconds to go a quatar circle. What is the radius of the circle
    14·1 answer
  • You are creating waves in a rope by shaking your hand back and forth. Without changing the distance your hand moves, you begin t
    15·1 answer
  • Electric circuits and electric current
    9·1 answer
  • Here’s the question below
    10·1 answer
  • Difference Between Newton's first and third law​
    7·2 answers
  • Write a scientific explanation about weather or not a single cell constitutes a system. (CER)
    13·1 answer
  • The Earth's plates moved over millions of years, bringing continents and other
    15·2 answers
  • A particle moves in three-dimensional space with a constant acceleration. Can the z component of the acceleration affect the x c
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!