Answer:
A. (0, 6) and (−2, 0)
Step-by-step explanation:
The given equations are:
and
We equate the two equations to find their point of intersection;
We equate everything to zero to get;
When x=0, y=3(0)+6=6
One solution is;
(0,6)
When x=-2,
y=3(-2)+6=0
Another solution is;
(-2,0)
Answer:
what did not understand (im a bot)
Step-by-step explanation:
<span>y-2>1/2(x-2) can be expanded as follows: y - 2 > (1/2)x - 1
Mult. all terms by 2 to remove the fractions:
2y - 4 > x - 2
Add 4 to both sides: 2y > x + 2
Div. both sides by 2: y > (1/2)x + 1 (answer)</span>
Answer: x^4
Step-by-step explanation:
1. Rewrite the expression in fraction form:
(3√x²)^6 = x^(2/3)^6
2 is the exponent, so when written in fraction form, it is the numerator. 3 is the index or root, so in fraction form it is the denominator.
2. Solve:
x^(2/3)^6 = x^(12/3) = x^4
Because the exponent 2/3 is raised to the power of 6, you can use the power rule, which basically just means that whenever an exponent is raised to an exponent, multiply them. So, 2/3 * 6 equals 12/3, and 12/3 equals 4, making your answer x^4.
Answer:
Step-by-step explanation:
Given;
-Ba+9=Q²a
To solve for "a", make "a" the subject of the formula.
First, collect similar terms together;
-Ba - Q²a = -9
multiply through by "-1" to remove the negative sign;
Ba + Q²a = 9
factor out a;
a(B + Q²) = 9
divide both sides of the equation by "(B + Q²) ";
Therefore, the value of "a" in the given expression is