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3 years ago

When is written in simplest radical form, which value remains under the radical?

Mathematics

1 answer:

Semenov [28]3 years ago

6 0

Answer:

The number that is a perfect square remains on the outside and the one that isn't, stays on the inside. For example, you can make the number 2 $\sqrt{3}$ only when the number on the outside is a perfect square. The original number was 4, so it reduced down to 2, and the other number stayed in the radical

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Solve for x

jekas [21]

option C is correct......

5 0

3 years ago

What is Sn for the arithmetic series in which a1=16 , an=98 and n =13?

N76 [4]

Answer:741

Step-by-step explanation:

Given

First term $a_1=16$

last term $a_n=98$

and no of terms $n=13$

And sum of n terms is given by

$S_n=\frac{n}{2}[a_1+a_n]$

$S_n=\frac{13}{2}[16+98]$

$S_n=\frac{13\times 114}{2}$

$S_n=13\times 57$

$S_n=741$

Sp sum of n terms is 741

3 0

4 years ago

the product of two consecutive positive even integers is 14 more than their sum. Set up an equation that can

alexandr1967 [171]

Required equation to determine two consecutive even number is $x^{2}-16=0$ and required numbers are 4 and 6.

<u>Solution:</u>

Given that product of two consecutive positive integer is 14 more that their sum. Need to create the equation and solve it to get two numbers.

Let’s assume first even number be represented by x.

So second consecutive even number will be $x + 2$

Sum of two consecutive number = $(x) + (x + 2)$

$\Rightarrow$ Sum of two consecutive number = $2x + 2$

Product of two consecutive number = $(x) \times(x+2)=x^{2}+2 x$

Product of two consecutive number is 14 more that sum of two consecutive numbers, so if we subtract 14 from product, we will get sum.

$\begin{array}{l}{\Rightarrow\left(x^{2}+2 x\right)-14=2 x+2} \\\\ {=>x^{2}+2 x-2 x-14-2=0} \\\\ {\Rightarrow x^{2}-16=0} \\\\ {\Rightarrow x^{2}-4^{2}=0} \\\\ {\Rightarrow x^{2}=4^{2}} \\\\ {\Rightarrow x=4}\end{array}$