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mars1129 [50]
3 years ago
9

The value v of your quarters in cents) is a function of n, the number of quarters you have.

Mathematics
1 answer:
Bas_tet [7]3 years ago
3 0

Answer:

a) (2, 0.5)  (4, 1)

b) V(n) = 0.25n

c) $2.50

d) # quarters = independent

value = dependent

Step-by-step explanation:

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You and your friends plan to attend the county fair this weekend. Admission to the fair is $5 and the cost per ride is $0.50. Ho
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$20- $5= $15 for rides. You can go on 30 rides.
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99 points help SHOW YOUR WORK Q+B=13. When B+3=0
belka [17]

Q+B=13. When B+3=0

You have 2 separate equations.

First solve the 2nd equation for B:

B +3 = 0

Subtract 3 from both sides:

B +3 - 3 = 0-3

Simplify:

B = -3


Now we have a value for B, we can replace b with -3 in the first equation and solve for Q:


Q + -3 = 13

Add 3 to each side:

Q + -3 + 3 = 13+3

Simplify:

Q = 16


So you have Q = 16 and B = -3

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3 years ago
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A block of metal with volume 15 m3 and density 8,800 kg/m3 is combined with another metal of mass 850 kg and volume 6.2 m3 to fo
boyakko [2]

Answer:

El aluminio es un metal ligero con una densidad de 2.70 g/cm3, y por ello, aunque las aleaciones de aluminio tienen características mecánicas relativamente bajas comparadas con las del acero, su relación resistencia-peso es excelente. Es precisamente debido a esto que el aluminio se utiliza cuando el peso es un factor importante, como ocurre en las aplicaciones aeronáuticas y de automoción.

 

Tabla 13.8. Propiedades mecánicas y aplicaciones de algunas aleaciones comerciales de aluminio.

El aluminio también responde fácilmente a los diferentes mecanismos de endurecimiento, tal como se recoge en la tabla 13.8, donde se observa que el mecanismo más notable es el de endurecimiento por precipitación, donde se consigue una dureza hasta 30 veces superior a la del aluminio puro.

Por otra parte, el aluminio no suele presentar un límite de resistencia a la fatiga bien definido, de modo que la fractura puede suceder incluso a niveles muy bajos. Debido a su bajo punto de fusión, el aluminio no se comporta bien a temperaturas elevadas. Finalmente, las aleaciones de aluminio tienen escasa dureza, lo que origina poca resistencia al desgaste abrasivo en ocasiones.

4 0
3 years ago
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Solve systems of equations by algebraically x-2y=7 <br> 2x+5y =5
Natali [406]

Answer:

(5,-1) or x=5 y=-1

Step-by-step explanation:

I used the substitution method to solve this!

<em>1. Pick one of your equations and solve for one of the variables. I chose the first equation and solved for x.</em>

x-2y=7

(Move the -2y to the other side of the equation in order to get the x by itself. You do the opposite, so it becomes +2y.)

x=2y+7

<em>2. Now take your second equation and plug in what you got for x into the x variable.</em>

2(2y+7)+5y=5

(Multiple 2 by everything inside of the parentheses.)

4y+14+5y=5

(We want to get the y by itself, so move the 14 to the other side.)

4y+5y=-14+5

(Combine all the like terms.)

9y=-9

(Divide the 9 from the y. What you do to one side you must do to the other.)

y=-1

<em>3. Since you have one variable solved for. Now take the first equation and plug in your y.</em>

x-2(-1)=7

(Multiple -2 by -1)

x+2=7

(Move the 2 to the other side in order to get the x by itself.)

x=5

<em>4. If needed, plug in your x and y values into the equations in order to check your answer.</em>

Hope this could help!

8 0
3 years ago
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Which expressions are equivalent to (2^5)^-2
Aleonysh [2.5K]
Answer: Choice B) 2^(-10) and 1/1024

------------------------------------------------------

Explanation:

We'll use these two rules
Rule 1: (a^b)^c = a^(b*c)
Rule 2: a^(-b) = 1/(a^b)

Using rule 1 above, we can say
(2^5)^(-2) = 2^(5*(-2)) = 2^(-10)
So 2^(-10) is one of the answers

Now use rule 2 to convert 2^(-10) into...
2^(-10) = 1/(2^10) = 1/1024
so 1/1024 is the other answer
6 0
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