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yanalaym [24]
3 years ago
5

Given the balanced equation representing a reaction: 4nh3 (g) + 5o2 (g) → 4no(g) + 6h2o(g) what is the number of moles of h2o(g)

formed when 2.0 moles of nh3 (g) react completely?
Chemistry
2 answers:
alexdok [17]3 years ago
6 0
To solve, you find the correct mole ratio from the given equation. The questions asks for how many moles of H2O from 2.0 moles of NH3(ammonia), so the mole ration is going to be 6:4.
6 moles of  H2O and 4 moles of NH3.

<u>Tip:</u>
We multiply the given with what we want divided by what we want to get rid of.

So, 2.0mol NH3 x 6mol H2O /4mol NH3.


The answer is  3 moles of H2O or 3mol H2O
pav-90 [236]3 years ago
4 0

Answer : The number of moles of H_2O formed is, 3 moles

Solution : Given,

Moles of NH_3 = 2.0 moles

Now we have to calculate the moles of H_2O

The given balanced chemical reaction is,

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)

From the balanced reaction, we conclude that

As, 4 moles of NH_3 react to give 6 moles of H_2O

So, 2.0 moles of NH_3 react to give \frac{6}{4}\times 2.0=3 moles of H_2O

Therefore, the number of moles of H_2O formed is, 3 moles

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What is the pH of this solution?
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Answer:

pH = 11.216.

Explanation:

Hello there!

In this case, according to the ionization of ammonia in aqueous solution:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:

Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}

However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:

1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M

Which is also:

[OH^-]=1.643x10^{-3}M

Thereafter we can compute the pOH first:

pOH=-log(1.643x10^{-3}M)\\\\pOH=2.784

Finally, the pH turns out:

pH=14-2.784\\\\pH=11.216

Regards!

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