Hi there are we safe and are you all safe
I don’t know how to
I don’t know how to
I don’t know how to
I don’t know how to
In the reduction-oxidation reaction given, Cu is reduced because it gained 2 electrons, on the other hand H2 is oxidized because it gained one electron. I hope this helps.
Answer:
only chlorine can expand its octet.
Explanation:
An atom can expand its octet is it has empty d orbital
the electronic configuration of given elements will be:
B : 1s2 2s2 2p1 [Valence shell n =2 no d orbital]
O :1s2 2s2 2p4 [Valence shell n =2 no d orbital]
F : 1s2 2s2 2p5 [Valence shell n =2 no d orbital]
Cl :1s2 2s2 2p6 3s2 3p5 3d0 [Valence shell n =2 no d orbital]
Out of given elements only chlorine has empty d orbitals in its valence shell
Thus only chlorine can expand its octet.
There is no comparable easy way to experimentally measure the change in entropy for a reaction
<span>Converting from mass (grams) to moles: Divide your initial mass by the molar mass of the compound as determined by the periodic table.<span>Converting from moles to mass (grams): </span>Multiply your initial mole value by the molar mass of the compound as determined by the periodic table.<span>Converting from volume (liters) to moles: </span>Divide your initial volume by the molar volume constant, 22.4 L.<span>Converting from moles to volume (liters): </span>Multiply your mole value by the molar volume constant, 22.4L.<span>Converting from particles (atoms, molecules, or formula units) to moles: </span>Divide your particle value by Avogadro’s number, 6.02×1023. Remember to use parentheses on your calculator!<span>Converting from moles to particles (atoms, molecules, or formula units): </span>Multiply your mole value by Avogadro’s number, 6.02×1023.<span>Mole-to-mole conversions: </span>Use the coefficients from your balanced equation to determine your conversion factor. Be sure your units cancel out so you end up with the correct mole value.</span>