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Katen [24]
3 years ago
10

Ana is going to the carnival. She wants to ride at least 5 rides, and she has $30 to spend. She wants to ride the roller coaster

s at least 3 times. Roller coaster rides cost $3 each, and other rides cost $2 each. Graph the system of inequalities to show all the possible combinations of tickets Ana can buy. List two possible combinations.
Mathematics
1 answer:
olga55 [171]3 years ago
5 0
She can ride the rollercoaster 4 times and other ones 9 times 4R + 9O < 30$ (less than or equal to sign) or

6 roller coasters and 6 others...

6R + 6O = 30$

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Which describes where living and nonliving parts of an environment interact with and rely on each other?
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B

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Based on Pythagorean identities, which equation is true? A. Sin^2 theta -1= cos^2 theta B. Sec^2 theta-tan^2 theta= -1 C. -cos^2
Arturiano [62]

Answer:

D

Step-by-step explanation:

our basic Pythagorean identity is cos²(x) + sin²(x) = 1

we can derive the 2 other using the listed above.

1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)

1 + tan²(x) = sec²(x)

2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)

cot²(x) + 1 = csc²(x)

A. sin^2 theta -1= cos^2 theta

this is false

cos²(x) + sin²(x) = 1

isolating cos²(x)

cos²(x) = 1-sin²(x), not equal to sin²(x)-1

B. Sec^2 theta-tan^2 theta= -1

1 + tan²(x) = sec²(x)

sec²(x)-tan(x) = 1, not -1

false

C. -cos^2 theta-1= sin^2

cos²(x) + sin²(x) = 1

sin²(x) = 1-cos²(x), our 1 is positive not negative, so false

D. Cot^2 theta - csc^2 theta=-1

cot²(x) + 1 = csc²(x)

isolating 1

1 = csc²(x) - cot²(x)

multiplying both sides by -1

-1 = cot²(x) - csc²(x)

TRUE

3 0
3 years ago
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Lelechka [254]

Answer:B

Step-by-step explanation:

5 0
3 years ago
Which of these people had balanced their checkbook correctly. Gary: the balance in his check register is $500 and the balance in
otez555 [7]

Gary should be the correct choice because when you balance their checkbook correctly you should have a balanced or equal amount in both your check register and your bank statement.

Good luck! Please let me know if I have chosen the wrong answer. All though I am very confident in my answer.

7 0
3 years ago
Read 2 more answers
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