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3 years ago

Find the perimeter.

Mathematics

1 answer:

lianna [129]3 years ago

4 0

Answer:

whole 23 1/5

hope it helps.....

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FIND: Good old y-intercept!

Nataly_w [17]

Answer: easy, to find the y- intercept you have to take a set of points and put it into slope form

Step-by-step explanation:

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4 years ago

Rectangle ABCD is congruent to rectangle. Which sequence of transformations could have been used to transform rectangle ABCD to

il63 [147K]

Rectangle ABCD was rotated 90° counterclockwise around the origin and then translated 8 units down.

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3 years ago

(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2

Montano1993 [528]

Answer:

$\dfrac{m^3}{16p^2q^2}$

Step-by-step explanation:

Given:

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}$

$m^{-1}=\dfrac{1}{m}$

$q^0=1$

$2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}$

$(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}$

$m^{-1}=\dfrac{1}{m}$

$2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}$

$\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}$

$(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}$

8 0

3 years ago

Gabrielle took a Spanish test with 50 questions and answered 44 of them correctly. What percent of the questions did Gabrielle a

mrs_skeptik [129]

She answered 88% correct. 44 times 2 is 88.

7 0

3 years ago

Read 2 more answers

PLEASEE HELPP ME IM DESPERATE

miss Akunina [59]

Answer:

I can help with Q "4" as -

It uses triangle congruence test - here we use - SAS, as

one side is equal as it is given

both the angles are 90 degree

and they share a same side

so -

8x = 6x + 5

8x - 6x = 5

2x = 5

x = 2.5

RU = 6x+ 5 = 6 (2.5) + 5 = 20

( I am not so sure but I think this is the answer )

3 0

3 years ago