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3 years ago

Find the perimeter.

Mathematics

1 answer:

lianna [129]3 years ago

4 0

Answer:

whole 23 1/5

hope it helps.....

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Help needed math 3 - 10 points read closely

inessss [21]

<h2>Hello!</h2>

The answer is:

The answer is the fourth option,

$f(-3)=-\frac{1}{3}$

Piecewise functions are functions that are composed by two or more expressions, the expression to use will depend of the domain or input that we need to evaluate.

We are given the piecewise function:

$\left \{ {{\frac{1}{x}, if x$

There, we know that:

We should use the first expression if the value to evaluate is less than -2.

So, for this case, the function will be:

$f(x)=\frac{1}{x}$

We should use the second expression if the value to evaluate is greater or equal than 2.

So, for this case, the function will be:

$f(x)=x^{2}$

Now, since we are given that the value to evaluate is -3, and its less than -2, we need to use the first expression, and evaluate it.

$-3$

So, evaluating the function we have:

$f(x)=\frac{1}{x}$

$f(-3)=\frac{1}{-3}$

$f(-3)=-\frac{1}{3}$

Hence, we have that the answer is the fourth option,

$f(-3)=-\frac{1}{3}$

Have a nice day!

7 0

3 years ago

Choose the correct classification of 3x^4 − 9x^3 − 3x^2 + 6.

aliina [53]

It's a 4th degree polynomial since the largest degree (exponent) is 4

6 0

4 years ago

Read 2 more answers

Find the median for the following set of data:<br><br> 13,26,35,44,38,12,47,23,26

WITCHER [35]

$\sf{\qquad\qquad\huge\underline{{\sf Answer}}}$

For unorganized data, median is the middle value when the numbers are arranged in ascending order.

Let's proceed ~

In ascending order :

12, 13, 23, 26, 26, 35, 38, 44, 47

So, for given data... median is 26

4 0

2 years ago

Read 2 more answers

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

3 years ago

Guided Practice

S_A_V [24]

Answer:

A.481.25

Step-by-step explanation:

d=rt

Plug in numbers

d=38.5(12.5)

d=481.25

8 0

3 years ago