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3 years ago

A car travels 300km in six hour. What is the average speed

Physics

1 answer:

KiRa [710]3 years ago

5 0

Answer:

Explanation:

The average speed of the car can be found by using the formula

$s = \frac{d}{t} \\$

d is the distance

t is the time taken

From the question we have

$s = \frac{300}{6} = 50 \\$

We have the final answer as

Hope this helps you

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At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 8.00 ✕ 106 m/s pe

KonstantinChe [14]

Answer:

4347.8 m/s

Explanation:

It is given that the radius of the circular path traversed by proton and electron is same. Also, we know that magnitude of charge on an electron and proton is same. Magnetic field strength is same for both.

$\frac{m_ev_e^2}{r}=qv_eB\\\frac{m_pv_p^2}{r}=qv_pB\\$

Take the ratio:

$m_ev_e=m_pv_p\\\Rightarrow v_p=\frac{m_e}{m_p}v_e\\\Rightarrow v_p=\frac{1}{1840}\times 8.0\times 10^6 m/s\\\Rightarrow v_p=4347.8m/s$

3 0

3 years ago

zepelin [54]

A I believe it would be true

8 0

3 years ago

A circuit contains two resistors in series. The voltage drop across the first is 10 V. The voltage drop across the second is als

Norma-Jean [14]

Hi there!

Voltage in a series can be expressed by the following:

$V_T = V_1 + V_2$

In words, the total voltage is equal to the sum of the individual voltage drops in a SERIES circuit.

We can solve for the total voltage:

$V_T = 10 + 10 = \boxed{\text{ D. 20 V}}$

6 0

2 years ago

A negative charge of - 8.0 x 10^-6 C exerts an attractive force of 12 N on a second charge that is

Umnica [9.8K]

Answer:

<h2>Magnitude of the second charge is $-4.17*10^{-7}C$ </h2>

Explanation:

According to columbs law;

F = $kq1q2/r^{2}$

F is the attractive or repulsive force between the charges = 12N

q1 and q2 are the charges

let q1 = - 8.0 x 10^-6 C

q2=?

r is the distance between the charges = 0.050m

k is the coulumbs constant =9*10⁹ kg⋅m³⋅s⁻⁴⋅A⁻²

On substituting the given values

12 = 9*10⁹*( - 8.0 x 10^-6)q2/0.050²

Cross multiplying

$0.03=9*10^{9}* -8.0*10^{-6} q2\\0.03 = -72*10^{3} q2\\q2 = \frac{0.03}{ -72*10^{3}} \\q2 = -4.17*10^{-7}C$

6 0

4 years ago

Read 2 more answers

A bird flies from the South Pole to the North Pole. Part of the journey is 1000 miles that takes 2 weeks. What is the bird’s vel

viktelen [127]

1000 miles = 1610km = 1.61x10^6m
2 weeks = 14 days = 14x24x1440

V=d/t = 1.61x10^6/14x24x1440
= 3.33m/s

6 0

3 years ago

Read 2 more answers