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BartSMP [9]
3 years ago
11

When he sees teachers encouraging other children to wait in the cafeteria until the first bell rings, Ian follows them. What typ

e of learning is Ian demonstrating?
Physics
2 answers:
Ostrovityanka [42]3 years ago
8 0
This is observational learning because Ian observed that his peers waited in the cafeteria until the first bell rings. He decided to imitate them.
Tresset [83]3 years ago
8 0

ANSWER: Ian is demonstrating a typical example of Observational Learning. An observational learning is a learning pattern which happens by observing the behavior of others. People generally follows a role model such as parent, sibling, relative or teachers and imitate them while they are doing their work, particularly in childhood. There are four steps of observational learning which are Attention, Memory, Initiation and Motivation.

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Furkat [3]
The acceleration should 5.4 m/s^2
4 0
3 years ago
ball A of mass 5.0 kg moving at 20 meters per second collides with ball B of unknown mass moving at 10. meters per second in the
antiseptic1488 [7]

Answer:The mass of ball B is 10 kg.

Explanation;

Mass of ball A = M_A=5 kg

Velocity of the ball A before collision:U_A=20 m/s

Velocity of ball A after collision=V_A=10 m/s

Mass of ball B= M_B

Velocity of the ball B before collision:U_B=10 m/s

Velocity of ball B after collision=V_B=15 m/s

M_AV_A+M_BV_B=M_AU_A+M_BU_B

5 kg\times 10 m/s+M_B\times 15=5 kg\times 20m/s+M_B\times 10m/s

M_B=10kg

The mass of ball B is 10 kg.

8 0
3 years ago
A 500 kg sack of coal falls vertically onto a 2000 kg railroad flatcar which was initially moving horizontally at 3 m/s. no exte
Zinaida [17]

Since there are no external forces, including friction, act on the flatcar. after the sack rests on the flatcar, we would assume that momentum is conserved. This means that

total momentum of car before collision = total momentum of car after collision.

Recall,

momentum = mass x velocity

From the information given,

mass of car before collision = 2000

velocity of car before collision = 3

Thus,

total momentum of car before collision = 2000 x 3 = 6000

Also,

mass of sack = 500

mass of car and sack after collision = 500 + 2000 = 2500

velocity after collision = v

momentum after collision = 2500 x v = 2500v

Since momentum is conserved, then

6000 = 2500v

v = 6000/2500

v = 2.4

the speed of the flatcar is 2.4 m/s

6 0
1 year ago
Find the voltage across the 15 Ω resistor. .<br> 35 Ω<br> 20 Ω<br> 15 Ω<br> 10 V
almond37 [142]

Answer:

35 Ω

Explanation:

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2 years ago
Iron ball sinks in water but not in mercury. Why?
Zigmanuir [339]

Answer:

mercury is more dense

Explanation:

8 0
3 years ago
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