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BartSMP [9]
2 years ago
11

When he sees teachers encouraging other children to wait in the cafeteria until the first bell rings, Ian follows them. What typ

e of learning is Ian demonstrating?
Physics
2 answers:
Ostrovityanka [42]2 years ago
8 0
This is observational learning because Ian observed that his peers waited in the cafeteria until the first bell rings. He decided to imitate them.
Tresset [83]2 years ago
8 0

ANSWER: Ian is demonstrating a typical example of Observational Learning. An observational learning is a learning pattern which happens by observing the behavior of others. People generally follows a role model such as parent, sibling, relative or teachers and imitate them while they are doing their work, particularly in childhood. There are four steps of observational learning which are Attention, Memory, Initiation and Motivation.

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At constant volume, the heat of combustion of a particular compound is − 3550.0 kJ / mol. When 1.075 g of this compound ( molar
swat32

Answer:

C=1,25\cdot 10^{5} kJ/^{\circ}C

Explanation:

First of all let's define the specific molar heat capacity.

C = \frac{-Q}{n\cdot \Delta T} (1)

Where:

Q is the released heat by the system

n is the number of moles

ΔT is the difference of temperature of the system  

Now, we can find n with the molar mass (M) the mass of the compound (m).

n=\frac{m}{M}=6.95\cdot 10^{-3} moles      

Using (1) we have:

C=\frac{-3550}{6.95\cdot 10^{-3} 4.073}

C=1,25\cdot 10^{5} kJ/^{\circ}C

I hope it helps!

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NaOH + FeCl3* Na Cl + Fe 10H)3<br> balanced
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2 years ago
An object is thrown upward with some velocity. If the object rises 77.5 m above the point of release, (a) how fast was the objec
jolli1 [7]

Answer:

v_o=39\ m/s\\t_m=4\ s

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

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The object referred to in the question is thrown from a height H=0 and the maximum height is hm=77.5 m.

(a)

To find the initial speed we solve for vo:

\displaystyle v_o=\sqrt{2gh_m}

v_o=\sqrt{2\cdot 9.8\cdot 77.5}

v_o=39\ m/s

(b)

The maximum time or the time taken by the object to reach its highest  point is calculated as follows:

\displaystyle t_m=\frac{v_o}{g}

\displaystyle t_m=\frac{39}{9.8}

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