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Mkey [24]
3 years ago
6

How do you know that oxygen was the gas removed from the volume of air and not another

Chemistry
1 answer:
klio [65]3 years ago
8 0
One way of knowing that oxygen was the gas removed from the volume of air and not another is to know what the volume of air is made of first. When the composition of the volume of air is already identified, then next would be the process of separating these elements from each other and as to which is to be separated first. This would usually lead to knowing their masses, their boiling and freezing points, the temperatures at which they condense, and so on. This is to identify their differences to each other and use those differences to successfully separate those elements to each other.
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Is color and odor a chemical property or physical property?
Alex_Xolod [135]
PHYSICAL PROPERTY...................
3 0
3 years ago
How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the so
expeople1 [14]

Answer:

2.72 grams

Explanation:

Complete question is

You are asked to pre pare a pH = 4.00 buffer starting from 1.50 L of 0.0200 M solution of benzoic acid

(C6H5COOH)

and any amount you need of sodium benzoate

(C6H5COONa)

How many grams of sodium benzoate should be added to prepare the buffer? Neglect the small volume change that occurs when the sodium benzoate is added.

Solution

Given

pH of the buffer solution = 4

Concentration of C6H5COOH = 0.02 M

Volume of the buffer solution = 1.50 L

K_a value for benzoic acid is 6.3 * 10^ {-5}

Concentration of sodium benzoate

pH = - log Ka + log \frac{C6H5COONa}{C6H5COOH}

Substituting the given values we get

log \frac{C6H5COONa}{C6H5COOH}  = 4 + log (6.3 * 10^ {-5})\\log \frac{C6H5COONa}{C6H5COOH}  = -0.20\\\frac{C6H5COONa}{C6H5COOH} = 10^{-0.2}\\{C6H5COONa} = 10^{-0.2} * 0.02\\{C6H5COONa} =  0.63 * 0.02\\{C6H5COONa} =  0.0126 M

Number of moles in sodium benzoate

= 0.0126 * 1.5 \\= 0.0189 Mol

Mass of sodium benzoate

0.0189 mol * 144.147 \frac{g}{mol} \\= 2.72 g

3 0
3 years ago
(Numerical problems) A car is running with the velocity of 72km/h. What will be it's velocity after 5s if it's acceleration is -
kodGreya [7K]

The car's velocity after 5s : 10 m/s

<h3>Further explanation</h3>

Given

velocity=v=72 km/h=20 m/s

time=t = 5 s

acceleration=a = -2 m/s²

Required

velocity after 5s

Solution

Straight motion changes with constant acceleration

\tt v_f=v_i+at

vf=final velocity

vi = initial velocity

Input the value :

\tt v_f=20+(-2).5\\\\v_f=20-10\\\\v_f=10~m/s

The car is decelerating (acceleration is negative) so that its speed decreases

4 0
3 years ago
A gaseous sample of pure methane, CH4, is found to occupy a volume of 20.0 L at 25℃ and 1 atm pressure. What volume of O2, at th
alexdok [17]
None of the above is the correct answer
7 0
4 years ago
Identify the group number of following oxides/hydrides in Mendeleev
Ivan

Answer:

See explanation

Explanation:

The oxides or hydrides are formed by exchange of valency between the two atoms involved. The group of the atom bonded to oxygen or hydrogen in the binary compound can be deduced by considering the subscript attached to the oxygen or hydrogen atom.

Now let us take the journey;

R2O3- refers to an oxide of a group 13 element, eg Al2O3

R2O - refers to an oxide of group a group 1 element e.gNa2O

RO2 - refers to an oxide of a group 14, 15 or 16 element such as CO2, NO2 or SO2

RH2 - refers to the hydride of a group 12 element Eg CaH2

R2O7 - refers to an oxide of a group 17 element E.g Cl2O7

RH3- refers to a hydride of a group 13 element E.g AlH3

5 0
3 years ago
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