Answer:
0.912 mL
Explanation:
3 Na2S(aq) + 2 FeCl3(aq) → Fe2S3(s) + 6 NaCl(aq)
FeCl3 is the limiting reactant.
Number of moles of iron III sulphide produced= 3.75g/87.92 g/mol = 0.043 moles
Hence actual yield of Iron III sulphide = 0.043 moles
Theoretical yield of Iron III sulphide = actual yield ×100%/ %yield
Theoretical yield of iron III sulphide= 0.043 ×100/75 = 0.057 moles of Iron III sulphide
From the reaction equation,
2moles of iron III chloride produced 1 mole of iron III sulphide
x moles of iron III chloride, will produce 0.057 of iron III sulphide
x= 2× 0.057= 0.114 moles of iron III chloride
But
Volume= number of moles/ concentration
Volume= 0.114/0.125
Volume= 0.912 mL
Answer:
One mole of a substance is equal to 6.022 × 10²³ units of that substance (such as atoms, molecules, or ions). The number 6.022 × 10²³ is known as Avogadro's number or Avogadro's constant. The concept of the mole can be used to convert between mass and number of particles
Answer:
2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O
H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O
Explanation:
2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O
H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O
H+
O2-
OH-
Ba2+
Ca2+
NO3-
P 5+, 3+, 3-
H2O
Ammonium sulfide
68,154 g/mol
41.10 percent nitrogen, 11.83 percent hydrogen, and 47.04 percent sulfur.
Answer:
40 atm.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 200 mL
Initial pressure (P₁) = 2 atm
Final volume (V₂) = 10 mL
Temperature = constant
Final pressure (P₂) =?
The final pressure of the gas can be obtained by using the Boyle's law equation as shown below:
P₁V₁ = P₂V₂
2 × 200 = P₂ × 10
400 = P₂ × 10
Divide both side by 10
P₂ = 400 / 10
P₂ = 40 atm
Thus, the final pressure of the gas is 40 atm.
