Answer:
The economics in costing is explained below in complete details.
Explanation:
The economic cost is the blend and mixture of wastes of any assets that have a worth connected to them by any one person. The economic cost is practiced largely by economists as a method to examine the prudence of one sequence of performance with that of another. The economic cost varies from accounting cost because it incorporates opportunity cost.
Ba(OH)2 can be neutralized by adding an acid to the solution. We can add HCl to produce:
Ba(OH)2 + 2HCl ===> BaCl2 + 2H2O ; producing a salt BaCl2 and water.
or we can add H2SO4 to produce:
Ba(OH)2 + H2SO4 ===> BaSO4 + 2H2O; producing a salt, BaSO4, and water. <span />
Single and Double Replacement reactions are exactly as they sound - they “replace” one or two components, depending on the type, with something else obtained in the reaction.
1. This is a double replacement reaction - see that the SO4 and the OH groups are trading what they’re paired with? OH starts paired with Aluminum, and ends up paired to the Hydrogen, and the SO4 starts with the Hydrogen, but ends up with the Aluminum. Two things being replaced - a double replacement reaction.
2. This is a single replacement reaction - Iron replaces the Hydrogen through the reaction, leaving the Hydrogen inbound afterwards; one thing being replaced - a single replacement reaction.
3. Like 1, this is a double replacement reaction - Fluorine and Oxygen trade partners. Two things being replaced - a double replacement reaction.
Number 4 isn’t complete, and I’m not sure about the goal of the practice problems, so I hope this helps enough to finish the work!
Answer:
900 J/mol
Explanation:
Data provided:
Enthalpy of the pure liquid at 75° C = 100 J/mol
Enthalpy of the pure vapor at 75° C = 1000 J/mol
Now,
the heat of vaporization is the the change in enthalpy from the liquid state to the vapor stage.
Thus, mathematically,
The heat of vaporization at 75° C
= Enthalpy of the pure vapor at 75° C - Enthalpy of the pure liquid at 75° C
on substituting the values, we get
The heat of vaporization at 75° C = 1000 J/mol - 100 J/mol
or
The heat of vaporization at 75° C = 900 J/mol
Answer: 14.3%Explanation: In order to find the mass percent of hydrogen in this compound, you must determine how many grams of hydrogen you'd get in 100 g of compound.
In your case, you know that an unknown mass of hydrogen reacts with 0.771 g of carbon to form 0.90 g of hydrocarbon, which is a compound that contains only carbon and hydrogen.
Use the total mass of the hydrocarbon to determine how many grams of hydrogen reacted with the carbon.
Now, if 0.90 g of this compound contain 0.129 g of hydrogen, it follows that 100 g of this compound will contain.
So, if 100 g of this compound contain 14.33 g of hydrogen, it follows that the mass percent of hydrogen is 14.3%
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