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Butoxors [25]
3 years ago
15

Anybody need a friend that is a girl? (not gf)

Chemistry
2 answers:
rewona [7]3 years ago
7 0

Answer: I don't think that this is a question for Brainly lol

Simora [160]3 years ago
4 0

Answer:

yesh

Explanation:

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How are physical and chemical changes different
Wittaler [7]

Answer:

physic

Explanation:

physical chnages are chnages to the appearance

chemical chnages are chnages like

color temperature chnaging fromna gas to a liquid etc

3 0
4 years ago
Read 2 more answers
What does potassium hydroxide and sulphuric acid make?
bekas [8.4K]

Base + Acid = Water + Salt

It makes salt water... water and potassium sulfate

Balanced rxn is:

2KOH + H2SO4 = 2H2O + KSO4



4 0
3 years ago
Read 2 more answers
What is the electrical charge of an anion?
Greeley [361]
A cation is a positively charged ion.
An anion is a negatively charged ion.
If it's neutral, it's just an ion.
6 0
3 years ago
Read 2 more answers
What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91
Vikentia [17]

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L

Temperature = 91^{o}C = (91 + 273) K = 364 K

As molar mass of O_2 is 32 g/mol. Hence, the number of moles of O_2 are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

PV = nRT\\P  \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

4 0
3 years ago
A researcher wants to determine if a unicellular organism he discovered is an autotroph or a heterotroph. He radioactively label
GaryK [48]

Answer:

A

Explanation:

Autotrophs utilize the energy from  sunlight to reduce carbon dioxide to carbohydrates (glucose). The energy from the sunlight is used to split water into H+ and O2- and the H+ used in the reduction process. The labeled carbon in the carbon dioxide will, therefore, be incorporated by the autotrophs in the carbohydrates made in photosynthesis.  

4 0
3 years ago
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