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Butoxors [25]
3 years ago
15

Anybody need a friend that is a girl? (not gf)

Chemistry
2 answers:
rewona [7]3 years ago
7 0

Answer: I don't think that this is a question for Brainly lol

Simora [160]3 years ago
4 0

Answer:

yesh

Explanation:

You might be interested in
Part A Name the complex ion [Fe(CN)6]^3- . The oxidation number of iron is +3. Part B Name the complex ion [Cu(NH3)2(H2O)4]^2+ .
zvonat [6]

Answer:

Part A: Hexacyanoferrate (III)

Part B: DiammintetraaquoCupperate (II)

Part C: Dichlorobis(ethylenediamine) Chromate (II)

Part D: Triaquocarbonylnickel (II) Sulphate

Part E: Potassium Dicarbonatedifluoroplatinate (II)

Explanation:

For naming the complex ions there is a specific rule

Nomenclature of the complex ions are as follow

  • write a correct formulae
  • Indicate the oxidation number of metal in the complex
  • The oxidation number should write in the roman numeral in perenthasis after metal name
  • Ligand named before the metal ion
  • Ligan can be named in following order

                  * 1st negative,  2nd neutral, 3rd positive

                  * If there are more than 2 same charged ligand the write in                      

                    alphabetical order.

  • Write prefix i.e di, tri, tetra for multiple monodentate ligands
  • Anions name end at ido the replace the final name.
  • Neutral ligands named as their usual name, but there are some exceptions such as

                                      NH3 named as ammine

                                      H2O names aqua or aquo

                                     CO named ascarbonyl

                                      NO named as nitrosyl

  • If the complex is an anion, then name of the central atom will end in -ate, and its Latin name will be used except for mercury
  • The name of full complex will end with cation or anion with separate word.  

Keeping the rules in mind the complexes named as following.

_________________________

Part A:

[Fe(CN)₆]³⁻

Name of the Complex : Hexacyanoferrate (III)  

___________________

Part B:

[Cu(NH₃)₂(H₂O)₄]²⁺

Name of the Complex : DiammintetraaquoCupperate (II)

_______________________

Part C

CrCl₂(en)₂

Name of the Complex :  Dichlorobis(ethylenediamine) Chromate (II)

________________________

Part C

[Ni(H₂O)₃(CO)]SO₄

Name of the Complex : Tetraaquocarbonylnickel (II) Sulphate

______________________

Part E

K₄[Pt(CO₃)₂F₂]

Name of the Complex : Potassium Dicarbonatedifluoroplatinate (II)

5 0
3 years ago
Suppose you have a system made up of water only, with the container and everything beyond being the surroundings. Consider a pro
Airida [17]

Answer:

Yes

Explanation:

The possibility of evaporating and condensing is a proof of reversible reaction

8 0
3 years ago
Read 2 more answers
Rewrite each percent as a fraction and decimal 56%
Tasya [4]
I know the decimal is .56 i hope someone knows the fraction
Add Me!
6 0
3 years ago
A solution contains some or all of the ions Cu²⁺, Al³⁺, K⁺, Ca²⁺, Ba²⁺, Pb²⁺, and NH₄⁺. The following tests were performed, in o
Nina [5.8K]

Answer:

Among given, the ions which are present in the given solution are:

Cu²⁺, Al³⁺ and K⁺

Among given, the ions which are absent in the given solution are:

Pb²⁺, Ca²⁺ and Ba²⁺

The ion which no conclusion is NH₄⁺.

Explanation:

Reagents given are used in salt analysis. The salt analysis is a qualitative analysis used for the identification of cations and anions of inorganic salts.

HCl is used for the identification of group I cations. As no reaction occurred when HCl is added to the solution, that means group I cations are absent.

So, among the given Pb²⁺ is a group I cation, therefore, Pb²⁺ is absent.

H₂S along with HCl is used for the identification group II salts.

Addition of Addition of H₂S with 0.2 M HCl produced a black solid, so, group II cation Cu²⁺ is present.

H₂S is used for the identification of group III cations.

When H₂S is added to the filtrate of group II, white precipitate is formed that means group III cations are present. Among group III cations, Al³⁺ is present.

Addition of (NH₄)₂HPO₄ in the presence of NH₃ is used for the identification of group IV cations.

As no precipitate is formed, therefore, group IV cations are absent.

So among given options, Ca²⁺ and Ba²⁺ are absent in the given solution.

The final supernatant when heated produces purple flame which indicates the presence of K⁺.

Therefore, among given, the ions which are present in the given solution are:

Cu²⁺, Al³⁺ and K⁺

Among given, the ions which are absent in the given solution are:

Pb²⁺, Ca²⁺ and Ba²⁺

The ion which no conclusion is NH₄⁺.

5 0
3 years ago
The carbon dioxide exhaled by astronauts can be removed from a spacecraft by reacting it with lithium hydroxide (LiOH). The reac
maks197457 [2]
Two astronauts would exhale about 40 moles of carbon dioxide daily.

Carbon dioxide reacts with lithium hydroxide in a 1 : 2 mole ratio. Set up a proportion:

 1 : 2 = 40 : x

Then, find x: <span>12=40x

</span> Cross multiply. x = 80 moles of LiOH per day for both astronauts
8 0
3 years ago
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