Answer: The answer is Sodium acetate.
Explanation: Hope this helps plz mark brainliest.
Answer:
−2399.33 kJ
Explanation:
If NH₄NO₃ reacts with fuel oil to give a ΔH of -7198 for every 3 moles of NH₄NO₃
What is the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction
∴ For every 1 mole, we will have
of the total enthaply of the 3 moles
so, to determine the 1 mole; we have:

= −2399.33 kJ
∴ the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction = −2399.33 kJ
if we did not use an excess of the BaCl2 solution it would decrease the mass percentage of sulfate in the unknown sample.
The net precipitation equation would be.
Ba2+(aq) + SO42-(aq) → BaSO4(s)
If BaCl2 (Ba2+) is not taken in excess then the precipitation would not be completed as some of the sulfate ions would still be remaining in the solution. This would decrease the mass percentage of sulfate in the unknown sample.
If some tiny pieces of filter paper still remained mixed with the precipitate(BaSO4) then the mass of sulfate would increase and it gives a high mass percentage of the sulfate.
mass percentage of sulfate = (mass of sulfate/mass of sample)*100
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Whatever is on one side of the equation needs to be the same as the other. So K2CrO4+NaHSO3+H2O=NaHSO4+KOH+Cr(OH)3 you need to balance the equation between the = to make a balanced equation.
Answer:
If they are pushing off the wall, it would be B, as they are going faster. If they are slowing down, it would probably be A, gradually getting slower.
Explanation: