How many grams are there in 7.5x10^23 molecules of H2SO4
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<u> </u> The pH of 0.035 M aqueous aspirin is 2.48
<u>Explanation:</u>
We are given:
Concentration of aspirin = 0.035 M
The chemical equation for the dissociation of aspirin (acetylsalicylic acid) follows:
<u>Initial:</u> 0.035
<u>At eqllm:</u> 0.035-x x x
The expression of for above equation follows:
We are given:
Putting values in above expression, we get:
Neglecting the value of x = -0.0037 because concentration cannot be negative
So, concentration of = x = 0.0033 M
- To calculate the pH of the solution, we use the equation:
We are given:
= 0.0033 M
Putting values in above equation, we get:
Hence, the pH of 0.035 M aqueous aspirin is 2.48