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4 years ago

5

What is the heat source for rock formation

1 answer:

Otrada [13]4 years ago

6 0

Answer:

Explanation:

The heat source for rock formation

Primordial heat: Some heat accumulated during the earth's formation and it is still available to drive the internal heat Engine of the earth. Some of these heat are used to melt rocks and produce magma.

Radioactive sources: Radioactive elements within the earth also serves as heat source for rock formation. Their spontaneous decay produce heat which are sufficient enough to generate enough thermal energy to melt and produce rocks.

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The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by in SI units. What is the freq

nata0808 [166]

Answer:

$f=1.98\times 10^5\ Hz$

Explanation:

The magnetic field of a plane-polarized electromagnetic wave moving in the z-direction is given by :

$B=1.2\times 10^{-6}\sin [2\pi (\dfrac{z}{240}-\dfrac{10^7t}{8})]$ .....(1)

The general equation of the magnetic field wave is given by :

$B=B_o\sin (kz-\omega t)$ ....(2)

Equation (1) is in form of equation (2), if we compare equation (1) and (2) we find that,

$\omega=\dfrac{10^7}{8}$

We need to find the frequency of the wave. It is given by :

$f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{10^7}{8\times 2\pi}\\\\f=1.98\times 10^5\ Hz$

So, the frequency of the wave is $1.98\times 10^5\ Hz$

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4 years ago

The filament of an incandescent light bulb is made of tungsten which has a thermal coefficient of resistivity of α = 4.4 x 10-3

grandymaker [24]

Answer:

The current when the filament at room temperature is 11.84 A.

Explanation:

Given that,

Thermal coefficient of resistivity $\alpha=4.4\times10^{-3}\ K^{-1}$

Initial temperature = 293 K

Voltage = 140 Volt

Final temperature = 2900 K

Current = 0.95 A

Suppose we find the numerical value of the current when the filament is at room temperature

So, We use the equation of resistance of a material changes with temperature

$R=R_{0}(1+\alpha(T_{2}-T_{1}))$ ....(I)

Using ohm's law for value of resistance

$V = I R$

$R = \dfrac{V}{I}$

Put the value of resistance in the equation (I)

$\dfrac{V}{I}=\dfrac{V}{I_{0}}(1+\alpha(T_{2}-T_{1}))$

$I_{0}=I(1+\alpha(T_{2}-T_{1}))$

Put the value into the formula

$I_{0}=0.95(1+4.4\times10^{-3}(2900-293))$

$I_{0}=11.84\ A$

Hence, The current when the filament at room temperature is 11.84 A.

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