It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating).
<span>All you need is F=(K*Q1*Q2)/r^2 </span>
<span>Just set F=the drag force and the electric field strength is (K*Q2)/r^2, plugging those values in gives you </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
Yo no me voy a ir a la cama a
Answer:
0.0360531138247 V/m
Explanation:
= Resistivity of gold = 
(General value)
I = Current = 940 mA
d = Diameter = 0.9 mm
A = Area = 
E = Electric field
Resistivity is given by
The electric field in the wire is 0.0360531138247 V/m
Answer:
The first graph is showing the constant acceleration (1 m/s)
Explanation:
The second graph showing the flexible velocity therefore a in the graph is different at t1, t2, t3, t4
The last graph is showing constant velocity therefore there is no acceleration (a = 0)
The CORRECT answer would be false. They are different and so therefore the answer is false.
Hope this helped ‼️
