14c³d²-21c²d³/14cd
= (196c^4d³-21c²d³)/ 14cd
= (196c³d²-21cd²)/14
= (28c³d²-3cd²)/2
I hope that's help !
Answer:
a) ![\log 52](https://tex.z-dn.net/?f=%5Clog%2052)
b) ![\log_57](https://tex.z-dn.net/?f=%5Clog_57)
Step-by-step explanation:
Use logarithm properties:
![\log_ab+\log_ac=\log_a(b\cdot c)\\ \\\log_ab-\log_ac=\log_a\dfrac{b}{c}](https://tex.z-dn.net/?f=%5Clog_ab%2B%5Clog_ac%3D%5Clog_a%28b%5Ccdot%20c%29%5C%5C%20%5C%5C%5Clog_ab-%5Clog_ac%3D%5Clog_a%5Cdfrac%7Bb%7D%7Bc%7D)
Then
a) ![\log 13+\log 4=\log 13\cdot 4=\log 52](https://tex.z-dn.net/?f=%5Clog%2013%2B%5Clog%204%3D%5Clog%2013%5Ccdot%204%3D%5Clog%2052)
b) ![\log_514-\log _52=\log _5\dfrac{14}{2}=\log _57](https://tex.z-dn.net/?f=%5Clog_514-%5Clog%20_52%3D%5Clog%20_5%5Cdfrac%7B14%7D%7B2%7D%3D%5Clog%20_57)
From -4 to 1 (range equals the y values)
Answer:
1oc IS ur answer
Step-by-step explanation:
i think
I think 104,000 is the answer because when 26,000 is double it's 52,000 so I doubled 52,000 and 104,000 is what I got.